使用BufferedReader / BufferedWriter的套接字連接

Question

我的服務器沒有向客戶端發送帶有BufferedWriter的響應。 似乎代碼停止在int amountOfNumbersToBeGenerated = Integer.parseInt(bufferedReader.readLine()); 我相信客戶端上的bufferedreader.readline()調用在某種意義上是引起和發出並阻塞了連接的。

import java.io.*;
import java.net.Socket;
import java.util.ArrayList;

public class ThreadedConnection implements Runnable {

    private Socket connection;
    private InputStream in;
    private OutputStream out;

    public ThreadedConnection(Socket connection) {
        this.connection = connection;
        try {
            this.in = this.connection.getInputStream();
            this.out = this.connection.getOutputStream();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

    @Override
    public void run() {
        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(in));
        BufferedWriter bufferedWriter = new BufferedWriter(new OutputStreamWriter(out));
        try {

            String lotteryType = bufferedReader.readLine(); //reads first line of input stream

            int amountOfNumbersToBeGenerated = Integer.parseInt(bufferedReader.readLine());
            System.out.println("3"+amountOfNumbersToBeGenerated);
            switch (lotteryType) {
                case "LuckyForLife":

                        generateLotteryNumbers(amountOfNumbersToBeGenerated, 48, 18, bufferedWriter);
                    break;
                case "MegaMillions":
                    generateLotteryNumbers(amountOfNumbersToBeGenerated, 70, 25, bufferedWriter);
                    break;
                case "PowerBall":
                    generateLotteryNumbers(amountOfNumbersToBeGenerated, 69, 26, bufferedWriter);
                    break;
                default:
                    break;
            }
            bufferedWriter.flush();
        } catch (IOException e) {
            e.printStackTrace();
        }finally {
            try {
                connection.close();
                bufferedReader.close();
                bufferedWriter.close();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
    }

    public void generateLotteryNumbers(int amountOfNumbersToBeGenerated, int upperLimitOfGeneratedNumbers, int upperLimitOfExtraNumber, BufferedWriter bufferedWriter){
        RandomNumberGenerator randomNumbers = new RandomNumberGenerator(amountOfNumbersToBeGenerated,upperLimitOfGeneratedNumbers);
        RandomNumberGenerator extraNumber = new RandomNumberGenerator(1,upperLimitOfExtraNumber);
        ArrayList randomNumbersArrayList = randomNumbers.NumberGenerator();
        ArrayList extraNumberArrayList = extraNumber.NumberGenerator();
        String randomNumbersString = randomNumbersArrayList.toString();
        randomNumbersString = randomNumbersString.substring(1, randomNumbersString.length()-1);
        String extraNumberString = extraNumberArrayList.toString();
        extraNumberString = extraNumberString.substring(1, extraNumberString.length()-1);

        try {
            bufferedWriter.write(randomNumbersString);
            bufferedWriter.newLine();
            bufferedWriter.write(extraNumberString);
            bufferedWriter.newLine();
            bufferedWriter.flush();
        } catch (IOException e) {
            e.printStackTrace();
        }

//        System.out.println(randomNumbersString);
//        System.out.println(extraNumberString);
    }
}

這是客戶端的代碼。 我認為第一個String gerneretedNumber = bufferedReader.readLine(); 造成了問題。 當沒有任何內容從服務器寫出，然后弄亂服務器端的讀取時，幾乎就像調用讀取一樣。 如果我阻止了兩個readline()調用，則服務器上的代碼可以工作，並且可以在控制台上打印出一些內容。

static void runClient(){
        OutputStream outputStream;
        InputStream inputStream;

        Socket client;
        BufferedWriter bufferedWriter;
        BufferedReader bufferedReader;

        try {
            System.out.println("Creating client socket ");
            client = new Socket("127.0.0.1", 5000);

            outputStream = client.getOutputStream();
            inputStream = client.getInputStream();
            bufferedWriter = new BufferedWriter(new 
OutputStreamWriter(outputStream));
            //bufferedReader = new BufferedReader(new 
InputStreamReader(System.in));
            bufferedReader = new BufferedReader(new 
InputStreamReader(inputStream));

            bufferedWriter.write("LuckyForLife");
            bufferedWriter.newLine();
            bufferedWriter.write("5");
            bufferedWriter.flush();

            String generetedNumber = bufferedReader.readLine();
            String extraNumber = bufferedReader.readLine();

                System.out.println(gerneretedNumber);
                System.out.println(extraNumber);


            System.out.println("Guess its null");
            bufferedReader.close();
            bufferedWriter.close();
            client.close();
        } catch (UnknownHostException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

如果需要更多信息，我很樂意將其發布。

Answer 1

您的客戶永遠不會發送第二個換行符。 給定您的協議，客戶端不會半關閉（輸出關閉），因此服務器無法檢測到流的末尾。

順便說一句，嘗試在關閉套接字（tcp RST）之前關閉流（tcp FIN）； 這更“合乎道德”！ 順便說一句，tcp rst是一個殺手，未決字節可能不會被刷新掉（盡管您在這里有很多刷新，但這只是個好習慣）。