反序列化和解析包含多個對象的JSON字符串

Question

我正在使用Newtonsoft.Json，想反序列化和解析一個JSON像這樣，在（數組？）中有多個點

{
    "dataFile": {
        "point": [
            {
                "ID": 1,
                "time": "17.55",
                "m_position": {
                    "x": 43.311744689941409,
                    "y": 147.30763244628907,
                    "z": 25.503124237060548
                }
            },
            {
                "ID": 2,
                "time": "17.55",
                "m_position": {
                    "x": 43.311744689941409,
                    "y": 147.30763244628907,
                    "z": 25.503124237060548
                }
            },
            {
                "ID": 3,
                "time": "17.55",
                "m_position": {
                    "x": 43.311744689941409,
                    "y": 147.30763244628907,
                    "z": 25.503124237060548
                }
            },
            {
                "ID": 4,
                "time": "17.55",
                "m_position": {
                    "x": 43.311744689941409,
                    "y": 147.30763244628907,
                    "z": 25.503124237060548
                }
            },
            {
                "ID": 5,
                "time": "17.55",
                "m_position": {
                    "x": 43.311744689941409,
                    "y": 147.30763244628907,
                    "z": 25.503124237060548
                }
            },
            {
                "ID": 6,
                "time": "17.55",
                "m_position": {
                    "x": 43.311744689941409,
                    "y": 147.30763244628907,
                    "z": 25.503124237060548
                }
            },
            {
                "ID": 7,
                "time": "17.55",
                "m_position": {
                    "x": 43.311744689941409,
                    "y": 147.30763244628907,
                    "z": 25.503124237060548
                }
            }
        ]
    }
}

我用它來反序列化（strJSON是我上面粘貼的json代碼）：

var jPosData = JsonConvert.DeserializeObject<jsonPosSample>(strJSON);

我的jsonPosSample類是通過復制json並將其粘貼為Paste Special> Paste JSON as Classes生成的

所以我的jsonPosSample類看起來像這樣：

    class jsonPosSample
{
    public class Rootobject
    {
        public Datafile dataFile { get; set; }
    }

    public class Datafile
    {
        public Point[] point { get; set; }
    }

    public class Point
    {
        public int ID { get; set; }
        public string time { get; set; }
        public M_Position m_position { get; set; }
    }

    public class M_Position
    {
        public float x { get; set; }
        public float y { get; set; }
        public float z { get; set; }
    }
}

編輯：回答評論

通過反序列化來運行json代碼：

      var jPosData = JsonConvert.DeserializeObject<jsonPosSample>(strJSON);
      debugOutput("Here's our JSON object: " + jPosData.ToString());

debugOutput打印出：

Here's our JSON object: Robbat.jsonPosSample

我正在努力了解如何將點存儲在數組中或將其打印出來。 我需要制作6個對象，然后以某種方式將它們存儲到數組中，對嗎？ 我該怎么做呢？

Answer 1

您提供了兩個問題樣本。

1. 您的json末尾缺少'}'。

2. JsonConvert.DeserializeObject（strJSON）; //由於您的datafile屬性位於此類內。

如果要對jsonPosSample類進行操作，則

public class jsonPosSample
{
   public Datafile dataFile { get; set; }
}

var result = JsonConvert.DeserializeObject<jsonPosSample>(strJSON);