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[英]How do I turn a dictionary with lists as values into a dictionary with integers as values?
[英]How do i turn a list with multiple values into a dictionary with only 2 values?
我有一個名為country_population的列表,看起來像這樣:
[
'Guam',
{'total_population': {'date': '2013-01-01', 'population': 163943}},
'Central%20African%20Republic',
{'total_population': {'date': '2013-01-01', 'population': 4665025}}
]
我試着做dict(country_population)
這給了我以下錯誤:
ValueError: dictionary update sequence element #0 has length 4; 2 is required
我了解我的清單有4個值,但是如何將它變成只有2個值的字典? 我想要一個看起來像這樣的結果:
country_population = {'Guam' : '163943, 'Central%20African%20Republic' :
'4665025' }
使用dict()
和zip
演示:
country_population = ['Guam', {'total_population': {'date': '2013-01-01', 'population': 163943}}, 'Central%20African%20Republic', {'total_population': {'date': '2013-01-01', 'population': 4665025}}]
print(dict((i[0], i[1]['total_population']["population"])for i in zip(country_population[0::2], country_population[1::2])))
輸出:
{'Central%20African%20Republic': 4665025, 'Guam': 163943}
你可以試試:
my_list = ['Guam', {'total_population': {'date': '2013-01-01', 'population': 163943}}, 'Central%20African%20Republic', {'total_population': {'date': '2013-01-01', 'population': 4665025}}]
# dictionary to store new results
result = {}
for i in range(0, len(my_list), 2):
result[my_list[i]] = my_list[i+1]['total_population']['population']
print(result)
結果:
{'Central%20African%20Republic': 4665025, 'Guam': 163943}
對於上面使用dictionary comprehension
代碼,您可以嘗試:
result = {my_list[i] : my_list[i+1]['total_population']['population']
for i in range(0, len(my_list), 2)}
您描述的結果無效,因為它具有多個名為Name
和Population
鍵。 我認為您想要的是“ Name
作為關鍵字,“ Population
作為值,您可以通過以兩個為增量跳過列表並將每對加到字典中來實現。
d=dict()
for i in range(len(country_population)/2):
d[country_population[2*i]] =
country_population[2*i+1]['total_population']['population']
d['Guam']
將是163943。
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