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[英]Newtonsoft Json Deserialization 1 json property to decimal or int c# properties
[英]Overwrite a Json Property in C# - Newtonsoft Json
因此,我正在制作一個小的JSON解析器。
這是我要解析的JSON:
{"158023":{"prices":{"xbox":{"LCPrice":"225,000","LCPrice2":"232,000","LCPrice3":"235,000","LCPrice4":"235,000","LCPrice5":"239,000","updated":"15 secs ago","MinPrice":"27,000","MaxPrice":"500,000","PRP":"41"},"ps":{"LCPrice":"228,000","LCPrice2":"231,000","LCPrice3":"232,000","LCPrice4":"233,000","LCPrice5":"235,000","updated":"9 mins ago","MinPrice":"30,000","MaxPrice":"550,000","PRP":"38"},"pc":{"LCPrice":"305,000","LCPrice2":"305,000","LCPrice3":"315,000","LCPrice4":"333,000","LCPrice5":"347,000","updated":"1 hour ago","MinPrice":"37,000","MaxPrice":"700,000","PRP":"40"}}}}
我有以下課程來表示Json對象。
public partial class Prices
{
[JsonProperty("158023")]
public Token TokenNumber { get; set; }
}
public partial class Token
{
[JsonProperty("prices")]
public PricesClass Prices { get; set; }
}
public partial class PricesClass
{
[JsonProperty("xbox")]
public Pc Xbox { get; set; }
[JsonProperty("ps")]
public Pc Ps { get; set; }
[JsonProperty("pc")]
public Pc Pc { get; set; }
}
public partial class Pc
{
[JsonProperty("LCPrice")]
public string LcPrice { get; set; }
[JsonProperty("LCPrice2")]
public string LcPrice2 { get; set; }
[JsonProperty("LCPrice3")]
public string LcPrice3 { get; set; }
[JsonProperty("LCPrice4")]
public string LcPrice4 { get; set; }
[JsonProperty("LCPrice5")]
public string LcPrice5 { get; set; }
[JsonProperty("updated")]
public string Updated { get; set; }
[JsonProperty("MinPrice")]
public string MinPrice { get; set; }
[JsonProperty("MaxPrice")]
public string MaxPrice { get; set; }
[JsonProperty("PRP")]
public string Prp { get; set; }
}
public partial class Prices
{
public static Prices FromJson(string json) => JsonConvert.DeserializeObject<Prices>(json, PriceConverter.Settings);
}
internal static class PriceConverter
{
public static readonly JsonSerializerSettings Settings = new JsonSerializerSettings
{
MetadataPropertyHandling = MetadataPropertyHandling.Ignore,
DateParseHandling = DateParseHandling.None,
Converters = {
new IsoDateTimeConverter { DateTimeStyles = DateTimeStyles.AssumeUniversal }
},
};
}
通過執行以下操作,我很容易解析JSON:
Prices prices = Prices.FromJson(myJson);
問題是當我想使用不同於158023的數字時,例如158025。
Price類的JsonProperty已經設置為“ 158023”,我不知道如何重命名。
TLDR:我有一個JSON對象,我想在反序列化之前重命名JsonProperty文本。
既然你不知道密鑰,使用Dictionary<string, Token>
而不是財產TokenNumber
類Prices
。
public partial class Prices
{
// Remove this property
// [JsonProperty("158023")]
// public Token TokenNumber { get; set; }
}
public partial class Prices
{
public static Dictionary<string, Token> FromJson(string json) => JsonConvert.DeserializeObject<Dictionary<string, Token>>(json, PriceConverter.Settings);
}
現在,結果將是一個字典,其中的鍵是作為字符串的令牌值,而該值是Token
對象。
您可以使用JsonExtensionData
和OnDeserialized
屬性:
public class Wrapper
{
public string Id { get; set; }
public Item Item { get; set; }
[JsonExtensionData]
private IDictionary<string, JToken> _additionalData;
[OnDeserialized]
private void OnDeserialized(StreamingContext context)
{
// Get the first key. If you have more than one, you may need
// to customize this for your use case
var id = _additionalData.Keys.FirstOrDefault();
if (id != null)
{
// Assign to our Id property
this.Id = id;
// Create a reader for the subobject
var itemReader = _additionalData[id].CreateReader();
var serializer = new JsonSerializer();
// Deserialize the subobject into our Item property
this.Item = serializer.Deserialize<Item>(itemReader);
itemReader.Close();
}
}
}
public class Item
{
public string Name { get; set; }
}
您可以在這里嘗試。 另外,您可以編寫一個JsonConverter
來實現相同的目的,或者執行Amir的建議。
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