語法錯誤：連接到wallaroo時語法無效

Question

我在運行twitter_client.py時遵循了本教程“ https://blog.wallaroolabs.com/2017/11/identifying-trending-twitter-hashtags-in-real-time-with-wallaroo/ ”，但出現此錯誤：

文件“ twitter_client.py”，行44打印（在％s：％s上連接到Wallaroo）％（wallaro_input_address）語法錯誤：無效的系統稅。

這是代碼

import socket
import sys
import requests
import requests_oauthlib
import json

# Replace the values below with yours
ACCESS_TOKEN = ''
ACCESS_SECRET = ''
CONSUMER_KEY = ''
CONSUMER_SECRET = ''
my_auth = requests_oauthlib.OAuth1(CONSUMER_KEY, 
CONSUMER_SECRET,ACCESS_TOKEN, ACCESS_SECRET)
def send_tweets_to_wallaroo(http_resp, tcp_connection):
for line in http_resp.iter_lines():
try:
full_tweet = json.loads(line)
if 'text' in full_tweet:
tweet_text = full_tweet['text'].encode('utf-8')
# send the length of text + 1 for newline represented as 5 ASCII
# characters, followed by the tweet text and \n
# e.g. if tweet text is 'Hello everyone!', send '00016Hello everyone!'
tcp_connection.sendall(str(len(tweet_text)+1).zfill(5) +
tweet_text + '\n')
except:
print ("Error decoding data received from Twitter!")
def get_tweets():
url = 'https://stream.twitter.com/1.1/statuses/filter.json'
query_data = [('locations', '-130,-20,100,50'), ('track', '#')]
query_url = url + '?' + '&'.join([str(t[0]) + '=' + str(t[1]) for t in 
query_data])
response = requests.get(query_url, auth=my_auth, stream=True)
return response
# Create a TCP/IP socket
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

# Connect to Wallaroo
wallaro_input_address = ('localhost', 8002)

print (connecting to Wallaroo on %s:%s) % (wallaro_input_address)
sock.connect(wallaro_input_address)

resp = get_tweets()
send_tweets_to_wallaroo(resp,sock)

請幫助...謝謝

Answer 1

嘗試使用此行而不是第44行：

print('connecting to Wallaroo on %s:%s' % (wallaro_input_address))

在python3中格式化的另一種方式：

print('connecting to Wallaroo on {}'.format(wallaro_input_address))