[英]SQL: How to subtract two fields belongs to same ID
假設每個Tx_ID只有2個條目,則可以嘗試以下操作:
SELECT Tx_ID,SUBTRACT(MAX(Tx_Time),MIN(Tx_Time)) FROM Tx_Table GROUP BY Tx_ID HAVING count(*) > 1
您可以使用LAG獲得先前的值。
然后使用它來獲取與當前記錄的差異。
SELECT
t.*,
t.tx_time - LAG(t.tx_time) OVER (PARTITION BY t.tx_id ORDER BY t.tx_time) AS timestamp_diff
FROM YOUR_TABLE t
以下內容應在第1次和第2次之間進行精確比較,以獲取Tx_ID
SELECT tx_id,
Subtract(Max(tx_time),Min(tx_time))
FROM tx_table T1
WHERE tx_time >=
(
SELECT Max(tx_time)
FROM tx_table T2
WHERE tx_time <
(
SELECT Max(tx_time)
FROM tx_table
WHERE
and tx_id = t1.tx_id)
AND tx_id = t1.tx_id)
GROUP BY tx_id
HAVING count(*) > 1
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