如何在pandas dataframe列中查找文本重合並計數

Question

我有一個這樣的熊貓數據框：

Text                       like=>apple        not=>here                  
i like apple                    0                 0
i do not like pears             0                 0
one two three                   0                 0
something here                  0                 0
something not here              0                 0
vla bla bla                     0                 0

我需要將列填充為：

Text                       like=>apple        not=>here                  
i like apple                    1                 0
i do not like pears             0                 0
one two three                   0                 0
something here                  0                 0
something not here              0                 1
vla bla bla                     0                 0

我不知道除“文本”列名稱以外的列名稱，我需要獲取列名稱並計算“文本”列的數據中的文本重合。

我唯一的想法是將列表中除“文本”列以外的所有列都通過逐行和逐列的名稱進行迭代並填充數據，但是我想存在一種更好的方法。

Answer 1

不用iterrows ，您可以按列實現此向量化。

In [41]: df.columns.to_series().drop('Text').values
Out[41]: array(['like=>apple', 'not=>here'], dtype=object)


In [42]: for ele in df.columns.to_series().drop('Text'):
    ...:     column_name = ele.replace('=>', ' ')
    ...:     df[ele] = df.Text.str.count(column_name)
    ...:     
    ...: 

In [43]: df
Out[43]: 
                  Text  like=>apple  not=>here
0         i like apple            1          0
1  i do not like pears            0          0
2        one two three            0          0
3       something here            0          0
4   something not here            0          1
5          vla bla bla            0          0