如何在Python 3的同一循環或函數中檢查用戶輸入的多個條件？

Question

我正在嘗試接受user-input但是我需要輸入一個整數，並且介於1到9之間。我嘗試在代碼中的幾個位置放置“ inrange（1,10）”，但沒有工作。 我需要程序不斷詢問用戶正確的輸入，直到他們提供正確的輸入為止。 到目前為止，我只能使用下面的代碼來確保它們的輸入是整數。 我將使用int(input("..."))而不是input("...") 。

while True:
    try:
        ui1 = int(input("Player 1, Your move. Select your move. "))
        break
    except ValueError:
        print("You have to choose a number between 1 and 9")
        continue

Answer 1

為什么不只檢查isdigit()和in range呢？

while True:
    ui1 = input("Player 1, Your move. Select your move. ")
    if ui1.isdigit() and int(ui1) in range(1,10):
        break
    print("You have to choose a number between 1 and 9")

# Continue code out of the loop

Answer 2

在中斷之前添加檢查，然后將錯誤消息移至循環末尾。

while True:
    try:
        ui1 = int(input("Player 1, Your move. Select your move. "))
        if 1 <= ui1 <= 9:
            break
    except ValueError:
        pass
    print("You have to choose a number between 1 and 9")

Answer 3

# beJeb
# Stack overflow -
# https://stackoverflow.com/questions/51202856/how-to-check-user-input-for-multiple-conditions-within-same-loop-or-function-in

# Our main function, only used to grab input and call our other function(s).
def main():

    while True:   
        try:
            userVar = int(input("Player 1, Your move. Select your move: "))
            break
        except ValueError:
            print("Incorrect input type, please enter an integer: ")

    # We can assume that our input is an int if we get here, so check for range
    checkRange = isGoodRange(userVar)

    # Checking to make sure our input is in range and reprompt, or print.
    if(checkRange != False):
        print("Player 1 chooses to make the move: %d" %(userVar))
    else:
        print("Your input is not in the range of 1-9, please enter a correct var.")
        main()

# This function will check if our number is within our range.
def isGoodRange(whatNum):
    if(whatNum < 10) & (whatNum > 0):
        return True

    else: return False

# Protecting the main function
if __name__ == "__main__":
    main()

注意：我測試了幾個輸入，因此我認為這應該足以幫助您理解該過程，如果不能，請發表評論，消息等。此外，如果此答案對您有所幫助，請選擇它作為回答來幫助其他人。

Answer 4

假設數字是您從用戶那里得到的輸入。

while(1): #To ensure that input is continuous
    number = int(input())
    if number>=1 and number<=10 and number.isdigit():
        break #if the input is valid, you can proceed with the number
    else:
        print("Enter a valid Number")

該號碼可用於進一步的操作。