[英]Create a JSON object from simple string in C#
我從命令行得到一個字符串作為響應。 我想將其轉換為json字符串,稍后將用於轉換為ac#對象。
The string Response(sub variable has this string as value)
Access Token 00D0E00000019dU!
Alias accp
Client Id SalesforceDevelopmentExperience
Connected Status Connected
Id 00D
Instance Url https://my.salesforce.com
Username ankur
嘗試通過以下代碼將其轉換為json
string[] subArray = sub.Split('\n');
string output = JsonConvert.SerializeObject(subArray);
var result = JsonConvert.DeserializeObject<Token>(output);
代幣類
public class Token
{
public string AccessToken { get; set; }
public string Alias { get; set; }
}
它給出了這個錯誤
Cannot deserialize the current JSON array (e.g. [1,2,3]) into type 'Token' because the type requires a JSON object (e.g. {"name":"value"}) to deserialize correctly.
To fix this error either change the JSON to a JSON object (e.g. {"name":"value"}) or change the deserialized type to an array or a type that implements a collection interface (e.g. ICollection, IList) like List<T> that can be deserialized from a JSON array. JsonArrayAttribute can also be added to the type to force it to deserialize from a JSON array.
Path '', line 1, position 1
。
轉換后的JSON
["Access Token 00D0E00000019dU!AQU","Alias accp","Client Id SalesforceDevelopmentExperience","Connected Status Connected","Id 00D","Instance Url https://my.salesforce.com","Username ankur"]
將字符串轉換為JSON / C#對象有幫助嗎?
忘記JSON並進行手動解析看起來要簡單得多。 例如:
//split up the source string into name value pairs
var nameValues = sub.Split('\n')
.Select(s => new
{
Name = s.Substring(0, 18).Trim(),
Value = s.Substring(18).Trim()
});
//Create the token object manually
var token = new Token
{
AccessToken = nameValues.Single(v => v.Name == "Access Token").Value,
Alias = nameValues.Single(v => v.Name == "Alias").Value
};
首先,您應該以不同的方式解析此“ sub”字符串。 其次,您應該創建JObject,而不是嘗試序列化字符串數組。
嘗試這個
// Splitting into string lines
var subArray = sub.Split('\n')
.Where(x => !string.IsNullOrEmpty(x));
JObject tokenJObj = new JObject();
foreach (var oneSub in subArray)
{
// I assume that the value will be after the last empty character
tokenJObj.Add(
oneSub.Substring(0, oneSub.LastIndexOf(' ')).Trim(),
oneSub.Substring(oneSub.LastIndexOf(' ') + 1));
}
string tokenStringJson1 = tokenJObj.ToString();
// or
string tokenStringJson2 = JsonConvert.SerializeObject(tokenJObj);
然后在模型內部的屬性上添加正確的屬性
public class Token
{
[JsonProperty("Access Token")]
public string AccessToken { get; set; }
// In this property attribute is not requied
[JsonProperty("Alias")]
public string Alias { get; set; }
}
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