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[英]How do I get the sum of years from date column in reference to each ticker?(Pandas)
[英]How do I get an age in years and date on pandas
這是我的數據
Customer_id Date-of-birth
1 1992-07-02
2 1991-07-03
這是我的代碼
import datetime as dt
df['now'] = dt.datetime.now()
df['age'] = df['now'].dt.date - df['Date-of-birth']
這是結果
Customer_id Date-of-birth age
1 1992-07-02 xxxx days
2 1991-07-03 xxxx days
我想要的結果是
Customer_id Date-of-birth age
1 1992-07-02 26 years 22 days
2 1991-07-03 27 years 21 days
現在讓我們通過df.dtypes
, Date-of-birth
是一個對象,因為它是基於下拉列表中的客戶輸入
我怎樣才能做到這一點? 我希望這個問題足夠清楚
將此解決方案與自定義功能一起使用,因為計算它並不容易,因為多年來:
from dateutil.relativedelta import relativedelta
def f(end):
r = relativedelta(pd.to_datetime('now'), end)
return '{} years {} days'.format(r.years, r.days)
df['age'] = df["Date-of-birth"].apply(f)
print (df)
Customer_id Date-of-birth age
0 1 1992-07-02 26 years 22 days
1 2 1991-07-03 27 years 21 days
輸入:
import pandas as pd
import datetime as dt
now = dt.datetime.now()
for i in range(0, len(df)):
diff = now - dt.datetime.strptime(df['Date-of-Birth'][i], '%Y-%m-%d')
years = diff.days // 365
days = diff.days - (years*365)
df['age'][i] = str(years) + ' years ' + str(days) + ' days'
print(df)
輸出:
Customer_id Date-of-Birth age
1 1992-07-04 26 years 25 days
2 1991-07-04 27 years 26 days
也許你可以使用類似下面的東西。 請注意,它依賴於平均年份為365.25
天這一事實,因此有時可能會休息一天。
import datetime as dt
def year_days_diff(x):
diff = (dt.datetime.now() - x).days
return str(int(diff / 365.25)) + ' years ' + str(int(diff / 365.25 % 1 * 365.25)) + ' days'
例:
birth_date = dt.datetime.now() - dt.timedelta(10000)
year_days_diff(birth_date)
輸出:
'27 years 138 days'
這可以通過四舍五入到年來給你年齡。
ref_date = dt.datetime.now()
df['age'] = df['Date-of-birth'].apply(lambda x: len(pd.date_range(start = x, end = ref_date, freq = 'Y')))
使用astype('<m8[Y]')
例如:
df['age'] = (pd.to_datetime('now') - df['Date-of-birth']).astype('<m8[Y]')
演示:
import pandas as pd
df = pd.DataFrame({"Date-of-birth": pd.to_datetime(['1992-07-24', '1991-07-24'])})
df["age"] = (pd.to_datetime('now') - df["Date-of-birth"]).astype('<m8[Y]')
print(df)
輸出:
Date-of-birth age
0 1992-07-24 25.0
1 1991-07-24 27.0
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