有什么辦法可以使這小段代碼更短？ （蟒蛇）

Question

first  = [0, 0, 0, 0]
second = [0, 0, 0, 0]
third  = [0, 0, 0, 0]
fourth = [0, 0, 0, 0]

while 0 in first and 0 in second and 0 in third and 0 in fourth:

頂部的列表以每個值保持為0開頭。隨着程序的進行，我計划將列表中的值從0更改為其他數字。 有效地，我想知道是否有方法可以重寫'while'語句以檢查0是否在任何列表中，而沒有長鏈的'while not in __ and not in __'等。

Answer 1

while all(0 in i for i in [first,second,third,fourth]):
   ...

如果要檢查列表中是否包含0，請執行以下操作：

while any(0 in i for i in [first,second,third,fourth]):
   ...

Answer 2

您可以串聯/合並所有列表並檢查真實性：

while not all(first+second+third+fourth):

這將檢查任何False-y值，如果為0，則返回True。

Answer 3

while 0 in first + second + third + fourth:
    # do stuff

Answer 4

您也可以map

ls = [first, second, third, fourth]
func = lambda x: 0 in x

while all(map(func, ls)):
    #dostuff

---

如果您想讓0 in first and 0 in second and ...話，請all使用。 如果0 in first 0 in second或0 in second 0 in first請使用any

Answer 5

while not any(map(all, [first, second, ...])):