[英]How to Identify a Weekend and Subtract it Automatically From my Time Differences in R
我正在編寫一個代碼,它使用兩個時間戳向量來為我提供特定進程所需的時間(簡單地說是difftime)。
但是在周末,時間應該停止。 因此,如果一個產品在周五進入並在周二離開,我必須減去周末時間。 因此,我需要有可能確定產品處理時間何時經過一個周末,周末會自動從時差中減去。
這些產品的識別問題比減法更多。
從chron
包中使用is.weekend
。
days<-seq.Date(as.Date("01-01-2017",format= "%d-%m-%Y"),as.Date("01-04-2017",format= "%d-%m-%Y"),by = "days")
library(chron)
days[is.weekend(days)]
[1] "2017-01-01" "2017-01-07" "2017-01-08" "2017-01-14" "2017-01-15" "2017-01-21" "2017-01-22"
[8] "2017-01-28" "2017-01-29" "2017-02-04" "2017-02-05" "2017-02-11" "2017-02-12" "2017-02-18"
[15] "2017-02-19" "2017-02-25" "2017-02-26" "2017-03-04" "2017-03-05" "2017-03-11" "2017-03-12"
[22] "2017-03-18" "2017-03-19" "2017-03-25" "2017-03-26" "2017-04-01"
weekdays.Date(days[is.weekend(days)])
[1] "Sunday" "Saturday" "Sunday" "Saturday" "Sunday" "Saturday" "Sunday" "Saturday"
[9] "Sunday" "Saturday" "Sunday" "Saturday" "Sunday" "Saturday" "Sunday" "Saturday"
[17] "Sunday" "Saturday" "Sunday" "Saturday" "Sunday" "Saturday" "Sunday" "Saturday"
[25] "Sunday" "Saturday"
weekdays
的功能可能在這里有所幫助:
weekdays(as.Date("2018-07-30"))
# [1] "monday"
因此,如果您傳遞日期對象的向量,您將能夠識別星期六和星期日。
例如:
which(weekdays(as.Date(c("2018-07-30", "2018-07-29", "2018-07-28", "2018-07-27"))) %in% c("saturday", "sunday"))
[1] 2 3
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