使用正則表達式分割多個字符串

Question

[Delta-1234, United-1345] Testing different airlines
[Delta-1234] Testing different airlines

我想在第一種情況下獲得Delta-1234和United-1345，在第二種情況下僅獲得Delta-1234。 是否可以使用findall？

Answer 1

您真的需要正則表達式嗎？ 您可以在方括號[和]之間找到元素

x = lambda s: s[s.index('['):s.index("]")+1]

string1 = "[Delta-1234, United-1345] Testing different airlines"
string2 = "[Delta-1234] Testing different airlines"

print(x(string1))
print(x(string2))

輸出

[Delta-1234, United-1345]
[Delta-1234]

Answer 2

如果要使用正則表達式，只需匹配[ ，然后（貪婪地）捕獲重復的非] ：

>>> regex = re.compile(r"\[([^\]]+)")
>>> re.findall(regex, "[Delta-1234, United-1345] Testing different airlines")
['Delta-1234, United-1345']
>>> re.findall(regex, "[Delta-1234] Testing different airlines")
['Delta-1234']

或使用后向

>>> regex = re.compile(r"(?<=\[)[^\]]+")
>>> re.findall(regex, "[Delta-1234, United-1345] Testing different airlines")
['Delta-1234, United-1345']
>>> re.findall(regex, "[Delta-1234] Testing different airlines")
['Delta-1234']

Answer 3

使用正則表達式實現此目的的另一種方法是：

import re

str1 = "[Delta-1234, United-1345] Testing different airlines"
str2 = "[Delta-1234] Testing different airlines"

regex_pattern = r"[^[]*\[([^]]*)\]"

print(re.match(regex_pattern, str1).groups()[0])
print(re.match(regex_pattern, str2).groups()[0])

它將打印

Delta-1234, United-1345
Delta-1234

Answer 4

鑒於：

s='''\
[Delta-1234, United-1345] Testing different airlines
[Delta-1234] Testing different airlines'''

你可以做：

>>> [e.split(', ') for e in re.findall(r'\[([^]]+)\]', s)]
[['Delta-1234', 'United-1345'], ['Delta-1234']]