[英]Obtaining the sub-array from the main array where each sub-array is shifted to right by one
[英]Get from a multimensional array only one sub-array by conditions
我有這個數組:
[
{u'createdAt': datetime.datetime(2018, 8, 1, 12, 3, 41), u'rawValue': -200.0, u'data_type': 's'},
{u'createdAt': datetime.datetime(2018, 8, 1, 11, 58), u'rawValue': -200.0, u'data_type': 's'},
{u'createdAt': datetime.datetime(2018, 8, 1, 11, 56, 51), u'rawValue': -200.0, u'data_type': 'm'}
]
我只想獲得一個與2個條件相對應的子數組:
1 : createdAt is bigger
2 : data_type = s
通過使用某些庫可以做到這一點嗎?
我試圖這樣:
dataToReturn = []
for data in datas:
if date_type in data['data_type']:
dataToReturn.append(data['data_type'])
return dataToReturn
但是似乎不是更好的主意。
預期產量:
['createdAt' : datetime.datetime(2018, 8, 1, 12, 3, 41), 'rawValue' : -200.0]
import datetime
d = [
{u'createdAt': datetime.datetime(2018, 8, 1, 12, 3, 41), u'rawValue': -200.0, u'data_type': 's'},
{u'createdAt': datetime.datetime(2018, 8, 1, 11, 58), u'rawValue': -200.0, u'data_type': 's'},
{u'createdAt': datetime.datetime(2018, 8, 1, 11, 56, 51), u'rawValue': -200.0, u'data_type': 'm'}
]
value = [i for i in d if i["data_type"] == "s"]
res = sorted(value, key=lambda x: x["createdAt"], reverse=True)
print(res[0])
print(len(value))
輸出:
{u'data_type': 's', u'rawValue': -200.0, u'createdAt': datetime.datetime(2018, 8, 1, 12, 3, 41)}
2
[i for i in d if i["data_type"] == "s"]
以使用data_type
==“ s”來獲取字典 sorted
按日期時間排序,然后使用index 您可以使用max
查找具有最大createdAt
時間的子數組
>>> import datetime
>>> lst = [{u'data_type': 's', u'rawValue': -200.0, u'createdAt': datetime.datetime(2018, 8, 1, 12, 3, 41)}, {u'data_type': 's', u'rawValue': -200.0, u'createdAt': datetime.datetime(2018, 8, 1, 11, 58)}, {u'data_type': 'm', u'rawValue': -200.0, u'createdAt': datetime.datetime(2018, 8, 1, 11, 56, 51)}]
>>> {str(k):v for k,v in max(filter(lambda x: x['data_type'] == 's', lst), key=lambda x: x['createdAt']).items() if str(k) in ['createdAt', 'rawValue']}
{'rawValue': -200.0, 'createdAt': datetime.datetime(2018, 8, 1, 12, 3, 41)}
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