[英]Crop image displayed in UIScrollview to rect displayed in overlay
我一直在環顧四周,找不到解決我問題的答案。 我有一個帶有嵌入式圖像視圖的滾動視圖。 您可以旋轉和縮放圖像。
視圖層次結構如下所示:
|-> UIViewController
|--> UIView
|---> UIScrollView
|----> UIImageView
UIView只是將控制器放在情節提要上時添加的默認視圖。
我還在頂視圖上繪制了一個疊加層,其外觀如下所示:
我需要做的是將圖像裁剪為覆蓋的大小。 疊加是實用地創建的,但我保留了用於方形中心的rect的引用。 用於生成疊加層的代碼是:
private void DrawOverlay()
{
var overlayPath = UIBezierPath.FromRect(View.Bounds);
// Calculate the size of the transparent area we need.
var rectSize = View.Frame.Width * 80 / 100;
nfloat clearStartX = View.Frame.GetMidX() - (rectSize / 2);
nfloat clearWidth = View.Frame.Size.Width - (clearStartX * 2);
nfloat clearStartY = View.Frame.GetMidY() - ((GetTopBarHeight() + rectSize) / 2);
nfloat clearHeight = clearWidth;
// Create the rectange for out transparent area;
TransparentRect = new CGRect(clearStartX, clearStartY, clearWidth, clearHeight);
var transparentPath = UIBezierPath.FromRect(TransparentRect);
// Apply the transparent box to our overall view.
overlayPath.AppendPath(transparentPath);
overlayPath.UsesEvenOddFillRule = true;
// Set the full colour.
var fillLayer = new CAShapeLayer();
fillLayer.Path = overlayPath.CGPath;
fillLayer.FillRule = CAShapeLayer.FillRuleEvenOdd;
fillLayer.FillColor = Colours.TransparentBackground.CGColor;
View.Layer.AddSublayer(fillLayer);
// Calculate the length of the white line we want.
var lineWidth = rectSize * 20 / 100;
// Create a bezier path based on the transparent rect we defined earlier, that and a combination of the line
// width we can plot each point to draw the lines. Each MoveTo defines the start of a new corner.
UIBezierPath path = new UIBezierPath();
path.MoveTo(new CGPoint(clearStartX, clearStartY + lineWidth));
path.AddLineTo(new CGPoint(clearStartX, clearStartY));
path.AddLineTo(new CGPoint(clearStartX + lineWidth, clearStartY));
path.MoveTo(new CGPoint((clearStartX + rectSize) - lineWidth, clearStartY));
path.AddLineTo(new CGPoint(clearStartX + rectSize, clearStartY));
path.AddLineTo(new CGPoint(clearStartX + rectSize, clearStartY + lineWidth));
path.MoveTo(new CGPoint(clearStartX, (clearStartY + rectSize) - lineWidth));
path.AddLineTo(new CGPoint(clearStartX, (clearStartY + rectSize)));
path.AddLineTo(new CGPoint(clearStartX + lineWidth, (clearStartY + rectSize)));
path.MoveTo(new CGPoint((clearStartX + rectSize) - lineWidth, (clearStartY + rectSize)));
path.AddLineTo(new CGPoint((clearStartX + rectSize), (clearStartY + rectSize)));
path.AddLineTo(new CGPoint((clearStartX + rectSize), (clearStartY + rectSize) - lineWidth));
// Apply the path and set the width and colour.
CAShapeLayer pathLayer = new CAShapeLayer();
pathLayer.Path = path.CGPath;
pathLayer.StrokeColor = UIColor.White.CGColor;
pathLayer.LineWidth = 5.0f;
pathLayer.FillColor = null;
View.Layer.AddSublayer(pathLayer);
}
我試圖像這樣裁剪圖像:
var imageref = ImageView.Image.CGImage.WithImageInRect(TransparentRect);
UIImage croppedImage = new UIImage(imageref);
這似乎也是大多數答案的指向方式。 但是,這對我不起作用。 首先,將變換應用於滾動視圖,而不是圖像視圖,因為手勢已綁定到滾動視圖,如下所示。
public override void ViewDidLoad()
{
base.ViewDidLoad();
NavigationItem.Title = "Crop Image";
var ButtonDone = new UIBarButtonItem("Done",
UIBarButtonItemStyle.Plain, (sender, e) =>
{
CropImage();
});
this.NavigationItem.SetRightBarButtonItem(ButtonDone, true);
DrawOverlay();
ScrollView.MinimumZoomScale = 1.0f;
ScrollView.MaximumZoomScale = 5.0f;
ScrollView.Delegate = this;
ScrollView.ContentSize = new CGSize(ImageView.Frame.Size.Width, ImageView.Frame.Size.Height);
var rotateGesture = new UIRotationGestureRecognizer((g) =>
{
g.View.Transform = CGAffineTransform.Rotate(g.View.Transform, g.Rotation);
g.Rotation = 0;
});
rotateGesture.Delegate = this;
ScrollView.AddGestureRecognizer(rotateGesture);
}
[Export("viewForZoomingInScrollView:")]
public UIView ViewForZoomingInScrollView(UIScrollView scrollView)
{
return ImageView;
}
[Export("gestureRecognizer:shouldRecognizeSimultaneouslyWithGestureRecognizer:")]
public bool ShouldRecognizeSimultaneously(UIGestureRecognizer gestureRecognizer, UIGestureRecognizer otherGestureRecognizer)
{
return true;
}
那么如何將圖像裁剪為透明的覆蓋矩形並保持縮放和旋轉變換呢?
感謝您對這個問題的任何幫助。
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