[英]Need help deserializing JSON Object returned from API
我有以下JSON輸出:
{{
"$type": "Asi.Soa.Core.DataContracts.PagedResult`1[[Asi.Soa.Core.DataContracts.GenericEntityData, Asi.Contracts]], Asi.Contracts",
"Items": {
"$type": "System.Collections.Generic.List`1[[Asi.Soa.Core.DataContracts.GenericEntityData, Asi.Contracts]], mscorlib",
"$values": [
{
"$type": "Asi.Soa.Core.DataContracts.GenericEntityData, Asi.Contracts",
"EntityTypeName": "14",
"Properties": {
"$type": "Asi.Soa.Core.DataContracts.GenericPropertyDataCollection, Asi.Contracts",
"$values": [
{
"$type": "Asi.Soa.Core.DataContracts.GenericPropertyData, Asi.Contracts",
"Name": "ResultRow",
"Value": "1"
},
{
"$type": "Asi.Soa.Core.DataContracts.GenericPropertyData, Asi.Contracts",
"Name": "Work Phone",
"Value": "(782) 438-7600"
},
{
"$type": "Asi.Soa.Core.DataContracts.GenericPropertyData, Asi.Contracts",
"Name": "Email",
"Value": "agsaz@rmax.net"
},
{
"$type": "Asi.Soa.Core.DataContracts.GenericPropertyData, Asi.Contracts",
"Name": "Full Name",
"Value": "Agazny"
},
{
"$type": "Asi.Soa.Core.DataContracts.GenericPropertyData, Asi.Contracts",
"Name": "iMISId",
"Value": "eg1"
},
{
"$type": "Asi.Soa.Core.DataContracts.GenericPropertyData, Asi.Contracts",
"Name": "Preferred Phone",
"Value": "780"
},
{
"$type": "Asi.Soa.Core.DataContracts.GenericPropertyData, Asi.Contracts",
"Name": "Organization",
"Value": "Re"
}
]
}
},
{
"$type": "Asi.Soa.Core.DataContracts.GenericEntityData, Asi.Contracts",
"EntityTypeName": "14",
"Properties": {
"$type": "Asi.Soa.Core.DataContracts.GenericPropertyDataCollection, Asi.Contracts",
"$values": [
{
"$type": "Asi.Soa.Core.DataContracts.GenericPropertyData, Asi.Contracts",
"Name": "ResultRow",
"Value": "2"
},
{
"$type": "Asi.Soa.Core.DataContracts.GenericPropertyData, Asi.Contracts",
"Name": "Work Phone",
"Value": "7802"
},
{
"$type": "Asi.Soa.Core.DataContracts.GenericPropertyData, Asi.Contracts",
"Name": "Email",
"Value": "aksm"
},
{
"$type": "Asi.Soa.Core.DataContracts.GenericPropertyData, Asi.Contracts",
"Name": "Full Name",
"Value": "Aji"
},
{
"$type": "Asi.Soa.Core.DataContracts.GenericPropertyData, Asi.Contracts",
"Name": "iMISId",
"Value": "esa"
},
{
"$type": "Asi.Soa.Core.DataContracts.GenericPropertyData, Asi.Contracts",
"Name": "Preferred Phone",
"Value": "780"
},
{
"$type": "Asi.Soa.Core.DataContracts.GenericPropertyData, Asi.Contracts",
"Name": "Organization",
"Value": "Hom"
}
]
}
}
我正在嘗試將此響應反序列化為可行的c#對象,並將其發布到接受完全不同的JSON格式的其他API。
到目前為止,這是我的代碼:
using (var client = new HttpClient())
{
// Format headers
client.DefaultRequestHeaders.Accept.Clear();
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
// Request token, and append to headers
await AddTokenToHeaders(client);
// Query HTTP Service
var response = await client.GetAsync(baseUrl + "api/IQA?querydocumentversionkey=f2005a6e-7f47-47c3-a7e7-bbd2a7b6ab38");
if (response.IsSuccessStatusCode)
{
var customer = await response.Content.ReadAsStringAsync();
JObject result = JObject.Parse(await response.Content.ReadAsStringAsync());
JArray a = (JArray)result["Items"]["$values"][0]["Properties"];
var test = a.AsJEnumerable();
但是,它沒有拾取我的整個JSON對象,因此無法將其映射到我的類的屬性:
--update。
我已經更新了代碼,並且能夠以所需的格式獲取Jarray,但是當我嘗試通過jObject枚舉到類客戶列表中時,嘗試轉換的屬性將返回null。
感謝您的回復。 通過使用以下代碼,我可以獲得所需的輸出。 但是,嘗試將輸出放入具有指定屬性的“客戶列表”類中,但是我在“客戶”類的屬性上得到了空值。
JObject result = JObject.Parse(await response.Content.ReadAsStringAsync());
JArray a = (JArray)result["Items"]["$values"];
List<Customer> items = ((JArray)a).Select(x => new Customer
{
ResultRow = (string)x["ResultRow"],
WorkPhone = (string)x["Work Phone"],
Email = (string)x["Email"],
FullName = (string)x["Full Name"],
iMISId = (string)x["iMISId"],
PreferredPhone = (string)x["Preferred Phone"],
Organization = (string)x["Organization"]
}).ToList();
public class Customer
{
[JsonProperty("ResultRow")]
public string ResultRow { get; set; }
[JsonProperty("Work Phone")]
public string WorkPhone { get; set; }
[JsonProperty("Email")]
public string Email { get; set; }
[JsonProperty("Full Name")]
public string FullName { get; set; }
[JsonProperty("iMISId")]
public string iMISId { get; set; }
[JsonProperty("Preferred Phone")]
public string PreferredPhone { get; set; }
[JsonProperty("Organization")]
public string Organization { get; set; }
}
您提供的代碼有誤。 您正在嘗試將Properties
轉換為JArray
作為對象時。
如果確實要在Properties
對象中使用數組,請執行以下操作:
JArray arr = (JArray)result["Items"]["$values"][0]["Properties"]["$values"];
否則,如果您正在尋找“ Properties
對象,則應該這樣做:
JObject obj = (JObject)result["Items"]["$values"][0]["Properties"];
最后,要重建Customer
實例列表,可以將以下邏輯與靜態方法結合使用:
var customersJson = (JArray)result["Items"]["$values"];
var customers = new List<Customer>();
foreach (JObject o in customersJson)
{
var customerJson = (JArray) o["Properties"]["$values"];
customers.Add(BuildCustomer(customerJson));
}
[...]
private static Customer BuildCustomer(JArray a)
{
return new Customer
{
ResultRow = GetValue(a, "ResultRow"),
WorkPhone = GetValue(a, "Work Phone"),
Email = GetValue(a, "Email"),
FullName = GetValue(a, "Full Name"),
iMISId = GetValue(a, "iMISId"),
PreferredPhone = GetValue(a, "Preferred Phone"),
Organization = GetValue(a, "Organization")
};
}
private static string GetValue(JArray array, string name)
{
JToken obj = array.FirstOrDefault(x => (string) x["Name"] == name);
if (obj == null)
return string.Empty;
return (string) obj["Value"];
}
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