查找其他列SQL中的列（字符串）的出現

Question

我嘗試在另一列中查找字符串的出現。

如果該字符串多次出現（在連接的列中），那么我想將其刪除。

我的數據（問題）摘錄見下圖。

這是我開始的SQL。

SELECT 
    t1.FIRST_NAME as FIRST_NAME, 
    t1.LAST_NAME as LAST_NAME, 
    t1.BIRTH_NAME as BIRTH_NAME, 
    compress(t1.FIRST_NAME) || compress(t1.LAST_NAME) || compress(t1.BIRTH_NAME) as full_name_no_space
FROM 
    atable t1

列4“ full_name_no_space”連接“ first_name”，“ last_name”和“ birth_name”。

數據不一致，意味着“ first_name”可以包含某人的名字和姓氏等。因此，在連接的列“ full_name_no_space”中存在重復的條目，我嘗試將其刪除。

Answer 1

嗯，這行得通嗎？

(case when compress(t1.first_name) like '%' || compress(t2.last_name) || '%' and
           t1.first_name <> t2.last_name
      then ''
      when compress(t1.first_name) like '%' || compress(t2.birth_name) || '%' and
           t1.first_name <> t2.birth_name
      then ''
      else compress(t1.first_name) 
 end) ||
 (case when compress(t1.last_name) like '%' || compress(t2.birth_name) || '%' and
           t1.first_name <> t2.birth_name
      then ''
      when compress(t1.last_name) like '%' || compress(t2.first_name) || '%' 
      then ''
      else compress(t1.last_name) 
 end) ||
(case when compress(t1.birth_name) like '%' || compress(t2.first_name) || '%' 
      then ''
      when compress(t1.birth_name) like '%' || compress(t2.last_name) || '%' 
      then ''
      else compress(t1.birth_name) 
 end) 

基本上，這是通過比較來確定是否已經匹配-如果不匹配，則將其包括在結果中。