如何將數字列表轉換為字母列表，Python

Question

python的新手，我正在嘗試編碼加密的消息

字母已被重寫如下：

cipher = [ "q", "a", "z", "w", "s", "x", "e", "d", "c", "r", "f", "v", "t", "g", "b", "y", "h", "n", "u", "j", "m", "i", "k", "o", "l", "p"]

idx = ord ("d") - ord ("a")

print(cipher[3])

輸出：w

input = str(input('Write Text: ')) #hello world used here
input = input.lower()
output = []
for character in input:
    number = ord(character) - 97
    output.append(number)
print(output)

輸出：

[7，4，11，11，14，-65，22，14，17，11，3]

不確定如何對應這兩個...

我試過了：

print(cipher[output])

返回TypeError：列表索引必須是整數或切片，而不是list

提前致謝

Answer 1

我認為您想要類似的東西：

deciphered = [cipher[i] if i > 0 else ' ' for i in output]
print(''.join(deciphered))

請注意i>0位在那里處理空間，這導致number -65 ...