類型為FilterAggregationBuilder的方法filter（FilterBuilder）不適用於參數（BoolQueryBuilder）

Question

我試圖首先通過ipgroup然后通過優先級對彈性查詢進行分組和分組。

TermsBuilder ipGroupAgg = AggregationBuilders.terms("by_ipGroup").field("IP Group")
                .subAggregation(AggregationBuilders.terms("by_Priority").field("Priority"));
        // create the bool filter for the condition above
        String[] priority= { "2", "3" };
        BoolQueryBuilder aggFilter = QueryBuilders.boolQuery().must(QueryBuilders.termsQuery("Priority", priority));

        // create the filter aggregation and add the year sub-aggregation
        FilterAggregationBuilder aggregation = AggregationBuilders.filter("agg").filter(aggFilter).subAggregation(ipGroupAgg );

但是最后一條語句給出了編譯錯誤，指出“針對filter（aggFilter）的 FilterAggregationBuilder類型的filter（FilterBuilder）方法不適用於參數（BoolQueryBuilder）”

Answer 1

您可能使用的是舊版ES，我的膽量告訴我1.7或更早的版本...在這種情況下，您需要使用以下代碼創建aggFilter ：

    BoolFilterBuilder aggFilter = FilterBuilders.boolFilter().must(FilterBuilders.termsFilter("Priority", priority));