方法未返回正確值

Question

我有一種方法可以檢查用戶是否要玩其他游戲，問題是，如果用戶輸入了無效的輸入，那么在正確輸入之后， anotherGame仍然設置為Y

當退出該方法時，即使他們輸入了錯誤的輸入， anotherGame的值仍為Y即使他們選擇了N

當此代碼塊運行時， anotherGame返回Y

else
{
     Console.WriteLine("ERROR: Invalid input (Y/N) only!");
     promptRedo(anotherGame);
}

代碼示例：

using System;

public class Program
{
    public static void Main()
    {
        string anotherGame = "y";
        while (anotherGame == "y")
        {
            anotherGame = promptRedo(anotherGame);
            Console.WriteLine(anotherGame);
        }
    }
    static String promptRedo(String anotherGame)
    {
        Console.Write("Would you like to play another game? (Y/N) => ");
        String input = Console.ReadLine().ToLower();
        if (input.Equals("y"))
        {
            anotherGame = "y";
        }
        else if (input.Equals("n"))
        {
            // get any key from user to exit program
            Console.WriteLine();
            Console.WriteLine("Thank you for playing!");
            Console.WriteLine("Press any key to exit ...");
            Console.ReadKey();
            anotherGame = "n";
            Console.WriteLine(anotherGame);
        }
        else
        {
            Console.WriteLine("ERROR: Invalid input (Y/N) only!");
            promptRedo(anotherGame);
        }
        return anotherGame;
    }
}

Answer 1

您不需要遞歸調用，只需刪除

promptRedo(anotherGame);

從內部的promptRedo功能的else部分promptRedo 。

Answer 2

此函數不需要傳遞參數。 而不是一遍又一遍地調用函數，只需將其放在循環中即可：

static String promptRedo()
{ 
    String anotherGame = ""
    do
    {
        Console.Write("Would you like to play another game? (Y/N) => ");
        String input = Console.ReadLine().ToLower();
        if (input.Equals("y"))
        {
            anotherGame = "y";
        }
        else if (input.Equals("n"))
        {
            // get any key from user to exit program
            Console.WriteLine();
            Console.WriteLine("Thank you for playing!");
            Console.WriteLine("Press any key to exit ...");
            Console.ReadKey();
            anotherGame = "n";
            Console.WriteLine(anotherGame);
        }
        else
        {
            Console.WriteLine("ERROR: Invalid input (Y/N) only!");
        }
    } while(anotherGame != "y" && anotherGame != "n")
    return anotherGame;
}

Answer 3

else
{
     Console.WriteLine("ERROR: Invalid input (Y/N) only!");
     promptRedo(anotherGame);
}

在這段代碼中，您只是調用hintRedo（）並在函數末尾返回anotherGame。 但是您應該從hintRedo（）返回。

您的代碼必須如下所示

else
{
     Console.WriteLine("ERROR: Invalid input (Y/N) only!");
     return promptRedo(anotherGame);
}

Answer 4

您尚未在else塊中將“ promptRedo（anotherGame）”方法分配給“ anotherGame”變量。

代替：

    else
    {
        Console.WriteLine("ERROR: Invalid input (Y/N) only!");
        promptRedo(anotherGame);
    }

您應該寫：

     else
    {
        Console.WriteLine("ERROR: Invalid input (Y/N) only!");
        anotherGame = promptRedo(anotherGame);
    }