python列表以格式化和替換數據

Question

從網站請求數據將返回一個看起來像這樣的列表。

[
     "https://site1.com/:hash",
     "https://site2.com/:hash",
     "https://site3.com/:hash",
     "https://site4.com/:hash",
     "https://site5.com/:hash"
]

我試圖遍歷該列表，並用一個等於cats的變量替換：hash 。 從列表的額外格式，加上額外的標點符號和搜索/替換，我感到很困惑。 任何其他幫助將不勝感激。

要求最終結果

https://site1.com/cats
https://site2.com/cats
https://site3.com/cats
https://site4.com/cats
https://site5.com/cats

到目前為止，我有以下內容

#!/usr/bin/env python3
import os
import requests
gw_path = 'https://raw.githubusercontent.com/ipfs/public-gateway-checker/master/gateways.json'

r = requests.get(gw_path)
text = r.text
for item in text:
   mod = item.replace(':hash', 'cats')
   print(mod)

。

Answer 1

如果a是初始列表，請使用列表推導 ：

a = ["https://site1.com/:hash",
      "https://site2.com/:hash",
      "https://site3.com/:hash",
      "https://site4.com/:hash",
      "https://site5.com/:hash"]

modified_a = [i.replace(':hash', 'cats') for i in a]

modified_a
['https://site1.com/cats',
 'https://site2.com/cats',
 'https://site3.com/cats',
 'https://site4.com/cats',
 'https://site5.com/cats']

和：

print "[%s]" % (','.join(modified_a)

[https://site1.com/cats,https://site2.com/cats,https://site3.com/cats,https://site4.com/cats,https://site5.com/cats]