從 Rest 服務器 C# 反序列化 json 列表

Question

只是有點卡在這里，我想從從服務器發回給我的 json 中獲取“通知”（列表）。 請參閱以下內容：

{"amountCashback": 0,"amountGratuity": 0, "amountTotal": 0, "notifications":["APPROVED" ],}

通知被枚舉；

notifications {
string = ['APPROVED', 'BAD_SWIPE', 'CARD_ERROR', 'CARD_EXPIRED', 'CARD_NOT_SUPPORTED', 'CONNECTING', 'CONNECTION_MADE', 'DECLINED', 'DECLINED_BY_CARD', 'INSERT_CARD', 'PIN_ENTRY', 'PLEASE_WAIT', 'PRESENT_CARD', 'PRESENT_ONLY_ONE_CARD', 'PROCESSING_ERROR', 'REMOVE_CARD', 'RETRYING', 'REQUEST_SENT', 'RE_PRESENT_CARD', 'SIGNATURE_VERIFICATION', 'SIGNATURE_VERIFICATION_PROCESS_COMPLETED', 'SIGNATURE_VERIFICATION_PROCESS_COULD_NOT_BE_COMPLETED', 'SIGNATURE_VERIFICATION_IN_PROGRESS', 'SIGNATURE_VERIFICATION_TIMEOUT', 'TRANSACTION_FINISHED', 'TRANSACTION_STARTED']

使用 json 到 c# 我創建了下面的類

class Polling
{
    public int amountBase { get; set; }
    public int amountCashback { get; set; }
    public int amountGratuity { get; set; }
    public int amountTotal { get; set; }
    public string authCode { get; set; }
    public string cardSchemeName { get; set; }
    public string cardHolderVerificationMethod { get; set; }
    public string location { get; set; }
    public List<string> notifications { get; set; }
    public string paymentMethod { get; set; }
    public string transactionResult { get; set; }
    public DateTime transactionTime { get; set; }
    public string transactionType { get; set; }
    public string endPoint { get; set; }
    public httpVerb httpMethod { get; set; }
    public string userPassword { get; set; }
    public int sendAmount { get; set; }
    public string requestId { get; set; }}

我希望能夠反序列化並抓取通知以在屏幕上顯示它們。 下面我添加了我為此使用的代碼。

 try
        {
            response = (HttpWebResponse)request.GetResponse();
            using (Stream responseStream = response.GetResponseStream())
            {
                if (responseStream != null)
                {
                    using (StreamReader reader = new StreamReader(responseStream))
                    {
                        strResponseValue = reader.ReadToEnd();
                    }
                    if (response.StatusCode == HttpStatusCode.OK)
                    {
                        dynamic jsonObjtpi = JsonConvert.DeserializeObject(strResponseValue);
                        string notifications = jsonObjtpi.notifications.ToString();
                        return notifications;
                    }

                }
            }
        }

謝謝各位，真的很感謝

Answer 1

Json 可以使用您的強類型Polling對象，例如

Polling polling = JsonConvert.DeserializeObject<Polling>(strResponseValue);

見https://www.newtonsoft.com/json/help/html/DeserializeObject.htm