結束我的秘密文字游戲並在 Python 中輸出用戶猜測計數

Question

我正在嘗試用 Python 編寫一個類似 Hangman 的文字游戲。 用戶可以猜測的次數沒有限制。

除了一個小問題外，我的游戲運行正常：當用戶猜出完整的單詞時，游戲並沒有結束並告訴他們他們贏了，以及猜了多少次。

def main():

    print("Welcome to the Secret Word Game!")
    print()


    word = ["m","o","u","n","t","a","i","n"]

    guessed = []
    wrong = []

    guesses = 0

    while True:

        out = ""
        for letter in word:
            if letter in guessed:
                out = out + letter
            else:
                out = out + "*"

        if out == word:
            print("You guessed", word)
            break

        print("Guess a letter from the secret word:", out)

        guess = input()

        if guess in guessed or guess in wrong:
            print("Already guessed", guess)
            guesses +=1
        elif guess in word:
            print("Correct!",guess,"is in the secret word!")
            guessed.append(guess)
            guesses+=1
        else:
            print("Wrong!")
            wrong.append(guess)
            guesses+=1

    print()
    print(guesses)




main()

Answer 1

您不會退出，因為您的終止條件不可能為 True：

    if out == word:

out是一個長度為 8 的字符串； word是 8 個單字符字符串的列表。 如果將word的初始化更改為

    word = "mountain"

然后您的程序運行良好，生成逐個猜測更新和適當數量的猜測。

Welcome to the Secret Word Game!

Guess a letter from the secret word: ********
n
Correct! n is in the secret word!
Guess a letter from the secret word: ***n***n
e
Wrong!
Guess a letter from the secret word: ***n***n
t
Correct! t is in the secret word!
Guess a letter from the secret word: ***nt**n
a
Correct! a is in the secret word!
Guess a letter from the secret word: ***nta*n
o
Correct! o is in the secret word!
Guess a letter from the secret word: *o*nta*n
i
Correct! i is in the secret word!
Guess a letter from the secret word: *o*ntain
f
Wrong!
Guess a letter from the secret word: *o*ntain
m
Correct! m is in the secret word!
Guess a letter from the secret word: mo*ntain
u
Correct! u is in the secret word!
You guessed mountain

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