如何從字符串中刪除00:00:00

Question

我正在嘗試使用熊貓從鏈接中刪除00:00:00（HH：MM：SS）。

https://www.z-ratos.com/orical/?from=USD&amount=0&date=2018-10-24 00:00:00

因此，我如何從我的鏈接中刪除此00:00:00，以便其正常工作。 我嘗試了這段代碼：

import requests
import pandas as pd
from datetime import *

# TO TAKE DATE DIFFERENCE IN LIST
today = datetime.today()
dates = pd.date_range('2018-10-13', today)
#print(dates)

for i in dates:
    #print(i)
    url = 'https://www.z-ratos.com/orical/?from=USD&amount=0&date%s'%i
    print(url)

輸出結果為：

https://www.z-ratos.com/orical/?from=USD&amount=0&date=2018-10-24 00:00:00
    .....
     ......
      ......

所需的輸出是：

https://www.z-ratos.com/orical/?from=USD&amount=0&date=2018-10-24

所以請提前幫助謝謝...

Answer 1

使用strftime("%Y-%m-%d")

例如：

import requests
import pandas as pd
from datetime import *

# TO TAKE DATE DIFFERENCE IN LIST
today = datetime.today()
dates = pd.date_range('2018-10-13', today)
#print(dates)

for i in dates:
    #print(i)
    url = 'https://www.z-ratos.com/orical/?from=USD&amount=0&date%s'%i.strftime("%Y-%m-%d")
    print(url)

Answer 2

對字符串使用DatetimeIndex.strftime ：

dates = pd.date_range('2018-10-13', today).strftime('%Y-%m-%d')

然后format或f-strings ：

for i in dates:
    #print(i)
    url = 'https://www.z-ratos.com/orical/?from=USD&amount=0&date={}'.format(i)
    #python 3.6+ solution
    #url = f'https://www.z-ratos.com/orical/?from=USD&amount=0&date={i}'
    print(url)

Answer 3

使用Datetime對象的date方法。 要從所有日期中刪除時間戳記：

dates = [d.date() for d in dates]

另外，當您遍歷日期時，只需使用i.date() 。