[英]Haskell Esqueleto 3 table join
這些是我嘗試從三個表進行SELECT的嘗試。 但是它們不編譯,而且我不理解該錯誤(我不知道為什么它期望一個元組(Entity Issue, b0)
而不是我認為代碼嘗試獲取的三元組)。
嘗試1:
{-# LANGUAGE ScopedTypeVariables #-}
{-# LANGUAGE NoImplicitPrelude #-}
{-# LANGUAGE OverloadedStrings #-}
{-# LANGUAGE TemplateHaskell #-}
{-# LANGUAGE MultiParamTypeClasses #-}
{-# LANGUAGE TypeFamilies #-}
module Handler.Support where
import Import hiding ((==.))
import qualified Database.Esqueleto as E
import Database.Esqueleto ((^.), (==.), (&&.))
import Data.Traversable
getSupportR :: CustomerId -> Handler Html
getSupportR customerId = do
customer_issues_followUps_list <- runDB $
E.select $
E.from $ \(i, f, c) -> do
E.where_ (i ^. IssueCustomerId ==. E.val customerId &&. i ^. IssueId ==. f ^. FollowUpIssueId &&. i ^. IssueCustomerId ==. c ^. CustomerId)
return (i, f, c)
let issues = map listToMaybe . group . sort . fst . unzip $ customer_issues_followUps_list
defaultLayout $ do
setTitle "Your Licenses"
$(widgetFile "support-display")
錯誤1:
/home/hhefesto/dev/laurus-nobilis/src/Handler/Support.hs:41:5: error:
• Couldn't match type ‘(ra, rb, rc)’ with ‘(Entity Issue, b0)’
arising from a functional dependency between:
constraint ‘Database.Esqueleto.Internal.Sql.SqlSelect
(E.SqlExpr (Entity Issue), E.SqlExpr (Entity FollowUp),
E.SqlExpr (Entity Customer))
(Entity Issue, b0)’
arising from a use of ‘E.select’
instance ‘Database.Esqueleto.Internal.Sql.SqlSelect
(a3, b3, c) (ra3, rb3, rc3)’
at <no location info>
• In the second argument of ‘($)’, namely
‘E.select
$ E.from
$ \ (i, f, c)
-> do E.where_
(i ^. IssueCustomerId ==. E.val customerId
&&.
i ^. IssueId ==. f ^. FollowUpIssueId
&&. i ^. IssueCustomerId ==. c ^. CustomerId)
return (i, f, c)’
In a stmt of a 'do' block:
customer_issues_followUps_list <- runDB
$ E.select
$ E.from
$ \ (i, f, c)
-> do E.where_
(i ^. IssueCustomerId
==. E.val customerId
&&.
i ^. IssueId
==. f ^. FollowUpIssueId
&&.
i ^. IssueCustomerId
==. c ^. CustomerId)
return (i, f, c)
In the expression:
do customer_issues_followUps_list <- runDB
$ E.select $ E.from $ \ (i, f, c) -> do ...
let issues
= map listToMaybe . group . sort . fst . unzip
$ customer_issues_followUps_list
defaultLayout
$ do setTitle "Your Licenses"
(do ...)
|
41 | E.select $
| ^^^^^^^^^^...
嘗試2:
{-# LANGUAGE ScopedTypeVariables #-}
{-# LANGUAGE NoImplicitPrelude #-}
{-# LANGUAGE OverloadedStrings #-}
{-# LANGUAGE TemplateHaskell #-}
{-# LANGUAGE MultiParamTypeClasses #-}
{-# LANGUAGE TypeFamilies #-}
module Handler.Support where
import Import hiding ((==.))
import qualified Database.Esqueleto as E
import Database.Esqueleto ((^.), (==.), (&&.))
import Data.Traversable
getSupportR :: CustomerId -> Handler Html
getSupportR customerId = do
customer_issues_followUps_list <- runDB $
E.select $
E.from $ \(i `E.InnerJoin` f `E.InnerJoin` c) -> do
E.on (c ^. CustomerId ==. i ^. IssueCustomerId)
E.on (i ^. IssueId ==. f ^. FollowUpIssueId)
E.where_ (i ^. IssueCustomerId ==. E.val customerId)
return (i, f, c)
let issues = map listToMaybe . group . sort . fst . unzip $ customer_issues_followUps_list
defaultLayout $ do
setTitle "Your Licenses"
$(widgetFile "support-display")
錯誤2:
/home/hhefesto/dev/laurus-nobilis/src/Handler/Support.hs:40:5: error:
• Couldn't match type ‘(ra, rb, rc)’ with ‘(Entity Issue, b0)’
arising from a functional dependency between:
constraint ‘Database.Esqueleto.Internal.Sql.SqlSelect
(E.SqlExpr (Entity Issue), E.SqlExpr (Entity FollowUp),
E.SqlExpr (Entity Customer))
(Entity Issue, b0)’
arising from a use of ‘E.select’
instance ‘Database.Esqueleto.Internal.Sql.SqlSelect
(a2, b2, c) (ra2, rb2, rc2)’
at <no location info>
• In the second argument of ‘($)’, namely
‘E.select
$ E.from
$ \ (i `E.InnerJoin` f `E.InnerJoin` c)
-> do E.on (c ^. CustomerId ==. i ^. IssueCustomerId)
E.on (i ^. IssueId ==. f ^. FollowUpIssueId)
....’
In a stmt of a 'do' block:
customer_issues_followUps_list <- runDB
$ E.select
$ E.from
$ \ (i `E.InnerJoin` f `E.InnerJoin` c)
-> do E.on
(c ^. CustomerId
==. i ^. IssueCustomerId)
E.on
(i ^. IssueId
==. f ^. FollowUpIssueId)
....
In the expression:
do customer_issues_followUps_list <- runDB
$ E.select
$ E.from
$ \ (i `E.InnerJoin` f `E.InnerJoin` c)
-> do ...
let issues
= map listToMaybe . group . sort . fst . unzip
$ customer_issues_followUps_list
defaultLayout
$ do setTitle "Your Licenses"
(do ...)
|
40 | E.select $
| ^^^^^^^^^^...
這是我的持久模型:
Customer
email Text
password Text
firstName Text
lastName Text
address1 Text
address2 Text
city Text
state Text
zipCode Text
country Text
phone Text
organization Text
UniqueCustomer email
deriving Typeable
deriving Show
deriving Eq
deriving Ord
License
licenseAlias Text
expirationDate UTCTime
assignedTo CustomerId
customerId CustomerId
deriving Show
deriving Eq
deriving Ord
Issue
customerId CustomerId
issueSummary Text
issueDetails Text
issueState Int
issueDate UTCTime
deriving Show
deriving Eq
deriving Ord
FollowUp
issueId IssueId
followUpDate UTCTime
followUpAuthor CustomerId
followUpText Text
deriving Show
deriving Eq
deriving Ord
-- Soon to be deleted:
Email
email Text
customerId CustomerId Maybe
verkey Text Maybe
UniqueEmail email
Comment json -- Adding "json" causes ToJSON and FromJSON instances to be derived.
message Text
customerId CustomerId Maybe
deriving Eq
deriving Show
如您所見,兩次嘗試中的錯誤是相同的:它期望使用元組而不是三元組。
任何幫助將不勝感激 :)
罪魁禍首在let
陳述中:
let issues = map listToMaybe . group . sort . fst . unzip $ customer_issues_followUps_list
fst
和unzip
與元組一起使用,因此編譯器暗示customer_issues_followUps_list
是元組。
為了解決這個問題,只需加上“-extra”你package.yml依賴(或者你的陰謀文件)並更換fst
並unzip
與fst3
和unzip3
在let
像這樣的語句:
let issues = map listToMaybe . group . sort . fst3 . unzip3 $ customer_issues_followUps_list
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