[英]Haskell Esqueleto 3 table join
这些是我尝试从三个表进行SELECT的尝试。 但是它们不编译,而且我不理解该错误(我不知道为什么它期望一个元组(Entity Issue, b0)
而不是我认为代码尝试获取的三元组)。
尝试1:
{-# LANGUAGE ScopedTypeVariables #-}
{-# LANGUAGE NoImplicitPrelude #-}
{-# LANGUAGE OverloadedStrings #-}
{-# LANGUAGE TemplateHaskell #-}
{-# LANGUAGE MultiParamTypeClasses #-}
{-# LANGUAGE TypeFamilies #-}
module Handler.Support where
import Import hiding ((==.))
import qualified Database.Esqueleto as E
import Database.Esqueleto ((^.), (==.), (&&.))
import Data.Traversable
getSupportR :: CustomerId -> Handler Html
getSupportR customerId = do
customer_issues_followUps_list <- runDB $
E.select $
E.from $ \(i, f, c) -> do
E.where_ (i ^. IssueCustomerId ==. E.val customerId &&. i ^. IssueId ==. f ^. FollowUpIssueId &&. i ^. IssueCustomerId ==. c ^. CustomerId)
return (i, f, c)
let issues = map listToMaybe . group . sort . fst . unzip $ customer_issues_followUps_list
defaultLayout $ do
setTitle "Your Licenses"
$(widgetFile "support-display")
错误1:
/home/hhefesto/dev/laurus-nobilis/src/Handler/Support.hs:41:5: error:
• Couldn't match type ‘(ra, rb, rc)’ with ‘(Entity Issue, b0)’
arising from a functional dependency between:
constraint ‘Database.Esqueleto.Internal.Sql.SqlSelect
(E.SqlExpr (Entity Issue), E.SqlExpr (Entity FollowUp),
E.SqlExpr (Entity Customer))
(Entity Issue, b0)’
arising from a use of ‘E.select’
instance ‘Database.Esqueleto.Internal.Sql.SqlSelect
(a3, b3, c) (ra3, rb3, rc3)’
at <no location info>
• In the second argument of ‘($)’, namely
‘E.select
$ E.from
$ \ (i, f, c)
-> do E.where_
(i ^. IssueCustomerId ==. E.val customerId
&&.
i ^. IssueId ==. f ^. FollowUpIssueId
&&. i ^. IssueCustomerId ==. c ^. CustomerId)
return (i, f, c)’
In a stmt of a 'do' block:
customer_issues_followUps_list <- runDB
$ E.select
$ E.from
$ \ (i, f, c)
-> do E.where_
(i ^. IssueCustomerId
==. E.val customerId
&&.
i ^. IssueId
==. f ^. FollowUpIssueId
&&.
i ^. IssueCustomerId
==. c ^. CustomerId)
return (i, f, c)
In the expression:
do customer_issues_followUps_list <- runDB
$ E.select $ E.from $ \ (i, f, c) -> do ...
let issues
= map listToMaybe . group . sort . fst . unzip
$ customer_issues_followUps_list
defaultLayout
$ do setTitle "Your Licenses"
(do ...)
|
41 | E.select $
| ^^^^^^^^^^...
尝试2:
{-# LANGUAGE ScopedTypeVariables #-}
{-# LANGUAGE NoImplicitPrelude #-}
{-# LANGUAGE OverloadedStrings #-}
{-# LANGUAGE TemplateHaskell #-}
{-# LANGUAGE MultiParamTypeClasses #-}
{-# LANGUAGE TypeFamilies #-}
module Handler.Support where
import Import hiding ((==.))
import qualified Database.Esqueleto as E
import Database.Esqueleto ((^.), (==.), (&&.))
import Data.Traversable
getSupportR :: CustomerId -> Handler Html
getSupportR customerId = do
customer_issues_followUps_list <- runDB $
E.select $
E.from $ \(i `E.InnerJoin` f `E.InnerJoin` c) -> do
E.on (c ^. CustomerId ==. i ^. IssueCustomerId)
E.on (i ^. IssueId ==. f ^. FollowUpIssueId)
E.where_ (i ^. IssueCustomerId ==. E.val customerId)
return (i, f, c)
let issues = map listToMaybe . group . sort . fst . unzip $ customer_issues_followUps_list
defaultLayout $ do
setTitle "Your Licenses"
$(widgetFile "support-display")
错误2:
/home/hhefesto/dev/laurus-nobilis/src/Handler/Support.hs:40:5: error:
• Couldn't match type ‘(ra, rb, rc)’ with ‘(Entity Issue, b0)’
arising from a functional dependency between:
constraint ‘Database.Esqueleto.Internal.Sql.SqlSelect
(E.SqlExpr (Entity Issue), E.SqlExpr (Entity FollowUp),
E.SqlExpr (Entity Customer))
(Entity Issue, b0)’
arising from a use of ‘E.select’
instance ‘Database.Esqueleto.Internal.Sql.SqlSelect
(a2, b2, c) (ra2, rb2, rc2)’
at <no location info>
• In the second argument of ‘($)’, namely
‘E.select
$ E.from
$ \ (i `E.InnerJoin` f `E.InnerJoin` c)
-> do E.on (c ^. CustomerId ==. i ^. IssueCustomerId)
E.on (i ^. IssueId ==. f ^. FollowUpIssueId)
....’
In a stmt of a 'do' block:
customer_issues_followUps_list <- runDB
$ E.select
$ E.from
$ \ (i `E.InnerJoin` f `E.InnerJoin` c)
-> do E.on
(c ^. CustomerId
==. i ^. IssueCustomerId)
E.on
(i ^. IssueId
==. f ^. FollowUpIssueId)
....
In the expression:
do customer_issues_followUps_list <- runDB
$ E.select
$ E.from
$ \ (i `E.InnerJoin` f `E.InnerJoin` c)
-> do ...
let issues
= map listToMaybe . group . sort . fst . unzip
$ customer_issues_followUps_list
defaultLayout
$ do setTitle "Your Licenses"
(do ...)
|
40 | E.select $
| ^^^^^^^^^^...
这是我的持久模型:
Customer
email Text
password Text
firstName Text
lastName Text
address1 Text
address2 Text
city Text
state Text
zipCode Text
country Text
phone Text
organization Text
UniqueCustomer email
deriving Typeable
deriving Show
deriving Eq
deriving Ord
License
licenseAlias Text
expirationDate UTCTime
assignedTo CustomerId
customerId CustomerId
deriving Show
deriving Eq
deriving Ord
Issue
customerId CustomerId
issueSummary Text
issueDetails Text
issueState Int
issueDate UTCTime
deriving Show
deriving Eq
deriving Ord
FollowUp
issueId IssueId
followUpDate UTCTime
followUpAuthor CustomerId
followUpText Text
deriving Show
deriving Eq
deriving Ord
-- Soon to be deleted:
Email
email Text
customerId CustomerId Maybe
verkey Text Maybe
UniqueEmail email
Comment json -- Adding "json" causes ToJSON and FromJSON instances to be derived.
message Text
customerId CustomerId Maybe
deriving Eq
deriving Show
如您所见,两次尝试中的错误是相同的:它期望使用元组而不是三元组。
任何帮助将不胜感激 :)
罪魁祸首在let
陈述中:
let issues = map listToMaybe . group . sort . fst . unzip $ customer_issues_followUps_list
fst
和unzip
与元组一起使用,因此编译器暗示customer_issues_followUps_list
是元组。
为了解决这个问题,只需加上“-extra”你package.yml依赖(或者你的阴谋文件)并更换fst
并unzip
与fst3
和unzip3
在let
像这样的语句:
let issues = map listToMaybe . group . sort . fst3 . unzip3 $ customer_issues_followUps_list
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