比較兩個具有重復和打印差異的字符串列表

Question

我是Python的新手，我的代碼有問題。 我想寫一個比較列表和打印到用戶的函數，哪些元素存在於list1中但不存在於lis2中。

例如，輸入可以是：

list1=["john", "jim", "michael", "bob"]
list2=["james", "edward", "john", "jim"]

然后輸出應該是：

Names in list1, but not in list2: Michael, Bob
Names in list2, but not in list1: James, Edward

謝謝你的幫助！

（編輯：到目前為止這是我的代碼：

def compare_lists(list1, list2):

    for name1 in list1:
        if name1 not in list2:
                  print("Names in list1, but not in list2: ", name1)

    for name2 in list2:
        if name2 not in list1:
                 print("Names in list1, but not in list2: ", name2)

我的問題是輸出打印兩次：

Names in list1, but not in list2: Michael
Names in list1, but not in list2: Bob
Names in list2 but not in list1: James
Names in list2 but not in list1: Edward

Answer 1

嘗試這個：

list1=["john", "jim", "michael", "bob"]
list2=["james", "edward", "john", "jim"]

names1 = [name1 for name1 in list1 if name1 not in list2]
names2 = [name2 for name2 in list2 if name2 not in list1] 
print(names1)
print(names2)

Answer 2

您可以將結果存儲在臨時字符串中，然后將其打印出來。

def compare_lists(list1, list2):

    str1 = ''
    for name1 in list1:
        if name1 not in list2:
            str1 += name1 + ' '
    print("Names in list1, but not in list2: ", str1)

    str2 = ''
    for name2 in list2:
        if name2 not in list1:
            str2 += name2 + ' '
    print("Names in list1, but not in list2: ", str2)

list1=["john", "jim", "michael", "bob"]
list2=["james", "edward", "john", "jim"]

compare_lists(list1, list2)