[英]How to get substring after pattern match? And remove found subString from Initial String
[英]How to match a given regex pattern to get a substring from a String
我有一個字符串 ex-“Abc Xyz Def OSSV-1810-017466-AB01 Def Utv” 如何編寫一個正則表達式來對“OSSV-1810-017466-AB01”等格式進行數學運算並僅從任何給定的字符串中提取它?
嘗試了什么:
public class RegexTest {
public static void main(String[] args) {
String str = "Abc Xyz Def OSSV-1810-017466-AB01 Def Utv";
Pattern pattern = Pattern.compile("[a-zA-Z\\-\\0-9\\-\\0-9\\-\\^A-Za-z0-9]");
Matcher matcher = pattern.matcher(str);
System.out.println(matcher.toString());
if(matcher.find()){
System.out.println("found" + matcher.group(1));
}
else{
System.out.println("not found");
}
}
}
您可以使用此模式[AZ]{4}-\\\\d{4}-\\\\d{6}-[AZ]{2}\\\\d{2}
。
matcher.group(1)
更改為matcher.group(0)
。
public static void main(String[] args) {
String input="Abc Xyz Def OSSV-1810-017466-AB01 Def Utv";
String regEx="([a-zA-Z ]*)((?:[A-Z]{4}-)(?:[0-9]{4}-)(?:[0-9]{6}-)(?:[A-Z0-9]{4}))([a-zA-Z ]*)";
Matcher matcher = Pattern.compile(regEx).matcher(input);
if(matcher.matches()) {
System.out.println(matcher.group(2));
}
}
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