How to match a given regex pattern to get a substring from a String

Question

i have a string for ex- "Abc Xyz Def OSSV-1810-017466-AB01 Def Utv" How to write a regex that mathches formats like "OSSV-1810-017466-AB01" and extract only that from any given string?

What is tried:

public class RegexTest { 
    public static void main(String[] args) { 
        String str = "Abc Xyz Def OSSV-1810-017466-AB01 Def Utv"; 
        Pattern pattern = Pattern.compile("[a-zA-Z\\-\\0-9\\-\\0-9\\-\\^A-Za-z0-9]"); 
        Matcher matcher = pattern.matcher(str); 
        System.out.println(matcher.toString()); 
        if(matcher.find()){ 
            System.out.println("found" + matcher.group(1)); 
        } 
        else{ 
            System.out.println("not found"); 
        } 
    } 
}   

Answer 1

You can use this pattern [AZ]{4}-\\\\d{4}-\\\\d{6}-[AZ]{2}\\\\d{2} .

Also change matcher.group(1) to matcher.group(0) .

Answer 2

public static void main(String[] args) {
    String input="Abc Xyz Def OSSV-1810-017466-AB01 Def Utv";

    String regEx="([a-zA-Z ]*)((?:[A-Z]{4}-)(?:[0-9]{4}-)(?:[0-9]{6}-)(?:[A-Z0-9]{4}))([a-zA-Z ]*)";
    Matcher matcher = Pattern.compile(regEx).matcher(input);            

    if(matcher.matches()) {         
        System.out.println(matcher.group(2));
    }
}