[英]Capture substring within delimiters and excluding characters using regex
正則表達式模式如何捕獲兩個分隔符之間的子字符串,但在第一個分隔符之后和最后一個分隔符(如果有)之前排除某些字符(如果有)? 輸入字符串看起來像這樣:
var input = @"Not relevant {
#AddInfoStart Comment:String:=""This is a comment"";
AdditionalInfo:String:=""This is some additional info"" ;
# } also not relevant";
捕獲應包含“{”和“}”之間的子字符串,但不包括任何空格、換行符和起始分隔符“{”之后的“#AddInfoStart”字符串(只要它們中的任何一個存在),並且不包括任何空格、換行符和“;” 和結束分隔符“}”之前的“#”字符(如果存在任何字符也是如此)。
捕獲的字符串應如下所示
Comment:String:=""This is a comment"";
AdditionalInfo:String:=""This is some additional info""
“:”和“:=”內部分隔符之前或之后可能有空格,而且“:=”之后的值並不總是標記為字符串,例如:
{ Val1 : Real := 1.7 }
對於數組,使用以下語法:
arr1 : ARRAY [1..5] OF INT := [2,5,44,555,11];
arr2 : ARRAY [1..3] OF REAL
這是我的解決方案:
代碼:
var input = @"Not relevant {
#AddInfoStart Comment:String:=""This is a comment"";
Val1 : Real := 1.7
AdditionalInfo:String:=""This is some additional info"" ;
# } also not relevant";
// remove content outside brackets
input = Regex.Replace(input, @".*\{", string.Empty);
input = Regex.Replace(input, @"\}.*", string.Empty);
string property = @"(\w+)";
string separator = @"\s*:\s*"; // ":" with or without whitespace
string type = @"(\w+)";
string equals = @"\s*:=\s*"; // ":=" with or without whitespace
string text = @"""?(.*?)"""; // value between ""
string number = @"(\d+(\.\d+)?)"; // number like 123 or with a . separator such as 1.45
string value = $"({text}|{number})"; // value can be a string or number
string pattern = $"{property}{separator}{type}{equals}{value}";
var result = Regex.Matches(input, pattern)
.Cast<Match>()
.Select(match => new
{
FullMatch = match.Groups[0].Value, // full match is always the 1st group
Property = match.Groups[1].Value,
Type = match.Groups[2].Value,
Value = match.Groups[3].Value
})
.ToList();
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