[英]Python:How to get all possbile matches with regex
我試圖在括號之間找到文本,但我想要這樣的東西
s="( abc (def) kkk ( mno) sdd ( xyz ) )"
p=re.findall(r"\(.*?\)",s)
for i in p:
print(i)
輸出:
( abc (def) ,
( mno),
( xyz )
預期的:
( abc (def) ,
( abc (def) kkk ( mno) ,
( abc (def) kkk ( mno) sdd ( xyz ) ,
( abc (def) kkk ( mno) sdd ( xyz ) ) ,
(def) ,
(def) kkk ( mno) ,
(def) kkk ( mno) sdd ( xyz ) ,
(def) kkk ( mno) sdd ( xyz ) ) ,
( mno) ,
( mno) sdd ( xyz ) ,
( mno) sdd ( xyz ) ) ,
( xyz ) ,
( xyz ) )
python regex 模塊不處理重疊匹配。 通過在文本中查找(
和)
的位置,為開始/結束值創建合理的元組並分割字符串,更容易獲得:
使用enumerate(iterable) 、 collections.defaultdict()和itertools.product() :
s="( abc (def) kkk ( mno) sdd ( xyz ) )"
# get positions of all opening and closing ()
from collections import defaultdict
d = defaultdict(list)
print(d)
for idx,c in enumerate(s):
if c in "()":
d[c].append(idx)
# combine all positions
from itertools import product
pos = list(product (d["("],d[")"]))
print(pos)
# slice the text if start < stop+1 else skip
for start,stop in pos:
if start < stop+1:
print(s[start:stop+1])
輸出:
# d
defaultdict(<class 'list'>, {'(': [0, 6, 16, 27], ')': [10, 21, 33, 35]})
# pos
[(0, 10), (0, 21), (0, 33), (0, 35), (6, 10), (6, 21), (6, 33), (6, 35),
(16, 10), (16, 21), (16, 33), (16, 35), (27, 10), (27, 21), (27, 33), (27, 35)]
# texts from pos
( abc (def)
( abc (def) kkk ( mno)
( abc (def) kkk ( mno) sdd ( xyz )
( abc (def) kkk ( mno) sdd ( xyz ) )
(def)
(def) kkk ( mno)
(def) kkk ( mno) sdd ( xyz )
(def) kkk ( mno) sdd ( xyz ) )
( mno)
( mno) sdd ( xyz )
( mno) sdd ( xyz ) )
( xyz )
( xyz ) )
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