如果對象的所有屬性都為空，則從對象數組中刪除對象

Question

我有一個對象數組，其中每個對象都有某些屬性。 我想從數組中刪除那些為對象內的所有屬性分配了空字符串的對象。

例子 ：

var x = [{
   "userName" : "XYZ",
   "age": 22,
   "gender": "M"
}, {
   "userName" : "ABC",
   "age": 23,
   "gender": "M"
}, {
   "userName" : "Mohan",
   "age":"",
   "gender": ""
}, {
   "userName" : "",
   "age":"",
   "gender": ""
}]

結果應該是

[{
   "userName" : "XYZ",
   "age": 22,
   "gender": "M"
}, {
   "userName" : "ABC",
   "age": 23,
   "gender": "M"
}, {
   "userName" : "Mohan",
   "age":"",
   "gender": ""
}]

Answer 1

您可以使用filter 、 every和Object.values的組合：

 const x = [{ "userName" : "XYZ", "age": 22, "gender": "M" }, { "userName" : "ABC", "age": 23, "gender": "M" }, { "userName" : "Mohan", "age":"", "gender": "" }, { "userName" : "", "age":"", "gender": "" }] const y = x.filter(z => !Object.values(z).every(w => w ==="")) console.log(y)