如果对象的所有属性都为空，则从对象数组中删除对象

Question

I have an array of objects, where each object has certain properties. I want to remove those objects from the array which have empty strings assigned for all properties within the object.

Example :

var x = [{
   "userName" : "XYZ",
   "age": 22,
   "gender": "M"
}, {
   "userName" : "ABC",
   "age": 23,
   "gender": "M"
}, {
   "userName" : "Mohan",
   "age":"",
   "gender": ""
}, {
   "userName" : "",
   "age":"",
   "gender": ""
}]

Result should be

[{
   "userName" : "XYZ",
   "age": 22,
   "gender": "M"
}, {
   "userName" : "ABC",
   "age": 23,
   "gender": "M"
}, {
   "userName" : "Mohan",
   "age":"",
   "gender": ""
}]

Answer 1

You can use a combination of filter , every and Object.values :

 const x = [{ "userName" : "XYZ", "age": 22, "gender": "M" }, { "userName" : "ABC", "age": 23, "gender": "M" }, { "userName" : "Mohan", "age":"", "gender": "" }, { "userName" : "", "age":"", "gender": "" }] const y = x.filter(z => !Object.values(z).every(w => w ==="")) console.log(y)