[英]C# - passing parameters by reference to constructor then using them from method
[英]Passing method with parameters with constructor
我有一個Manager類DataManger.cs,其中包含一種從特定人員獲取數據的方法。
public class DataManager
{
public DataType GetDataByIdNameAge (uint id, string name, int age)
{...}
}
我有Builder類,它創建Office類:
public class Builder
{
private DataManager _dataManager;
public Builder()
{
_dataManager = new DataManager();
}
// Creates multiple Office objects
public void Create()
{
var office = new Office();
}
}
public class Office
{
private Func<UInt32, UInt32, UInt32> _getDataByIdNameAge { get; }
public Office(Func<uint, string, int> getDataByIdNameAge )
{
_getDataByIdNameAge = getDataByIdNameAge ;
}
}
現在,我想將方法GetDataByIdNameAge(uint id,字符串名稱,int age)傳遞給每個創建的Office對象,並在其中使用它。 但是我現在不知道如何創建Office對象來傳遞方法。
只需傳遞沒有括號的方法名即可。
public class DataManager
{
public DataType GetDataByIdNameAge (uint id, string name, int age)
{...}
}
public class Builder
{
private DataManager _dataManager;
public Builder()
{
_dataManager = new DataManager();
}
// Creates multiple Office objects
public void Create()
{
var office = new Office(_dataManager.GetDataByIdNameAge); // <---
}
}
public class Office
{
// LMFTFU
private Func<uint, string, int, DataType> _getDataByIdNameAge { get; }
// ^^^^^^^^ don't forget the return datatype
public Office(Func<uint, string, int, DataType> getDataByIdNameAge )
{
_getDataByIdNameAge = getDataByIdNameAge;
}
}
我傾向於將DataManager抽象到IDataManager接口,然后Office將有一個IDataManager對象,它將用於任何“數據管理”,如下所示:
public class DataType
{
}
public interface IDataManager
{
DataType GetDataByIdNameAge(uint id, string name, int age);
}
public class DataManager : IDataManager
{
public DataType GetDataByIdNameAge(uint id, string name, int age)
{
return null;
}
}
public class Builder
{
// Creates multiple Office objects
public void Create()
{
var office = new Office(new DataManager());
}
}
public class Office
{
private IDataManager dataManager;
public Office(IDataManager dataManager)
{
this.dataManager = dataManager;
}
public void DoSomething()
{
DataType dataType = dataManager.GetDataByIdNameAge(1, "SomeName", 18);
}
}
我認為這比以Func傳遞方法的細節更為優雅。
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