[英]How to fix the labeling of a regression line equation on graph (using ggplot2)
當我在rstudio中運行以下代碼(請參見下文)時,除線性回歸線方程式之外,其他所有內容看起來都很不錯。 我沒有得到y = 3.142x -4.751,而是得到y = c(3.142)xc(-4.751)。
我該怎么做才能解決此問題? 提前非常感謝您。
set.seed(3L)
library(ggplot2)
df <- data.frame(x = c(1:100))
df$y <- 2 + 3 * df$x + rnorm(100, sd = 40)
lm_eqn <- function(df){
# browser()
m <- lm(y ~ x, df)
a <- coef(m)[1]
a <- ifelse(sign(a) >= 0,
paste0(" + ", format(a, digits = 4)),
paste0(" - ", format(-a, digits = 4)) )
eq1 <- substitute( paste( italic(y) == b, italic(x), a ),
list(a = a,
b = format(coef(m)[2], digits=4)))
eq2 <- substitute( paste( italic(R)^2 == r2 ),
list(r2 = format(summary(m)$r.squared, digits = 3)))
c( as.character(as.expression(eq1)), as.character(as.expression(eq2)))
}
labels <- lm_eqn(df)
p <- ggplot(data = df, aes(x = x, y = y)) +
geom_smooth(method = "lm", se=FALSE, color="red", formula = y ~ x) +
geom_point() +
geom_text(x = 75, y = 90, label = labels[1], parse = TRUE, check_overlap = TRUE ) +
geom_text(x = 75, y = 70, label = labels[2], parse = TRUE, check_overlap = TRUE )
print(p)
在函數lm_eqn
, format
函數給出了命名向量,通過刪除名稱可以解決問題,如下所示:
set.seed(3L)
library(ggplot2)
df <- data.frame(x = c(1:100))
df$y <- 2 + 3 * df$x + rnorm(100, sd = 40)
lm_eqn <- function(df){
# browser()
m <- lm(y ~ x, df)
a <- coef(m)[1]
a <- ifelse(sign(a) >= 0,
paste0(" + ", format(a, digits = 4)),
paste0(" - ", format(-a, digits = 4)) )
b <- format(coef(m)[2], digits=4)
names(a) <- names(b) <-NULL
eq1 <- substitute( paste( italic(y) == b, italic(x), a ),
list(a = a,
b = b))
eq2 <- substitute( paste( italic(R)^2 == r2 ),
list(r2 = format(summary(m)$r.squared, digits = 3)))
c( as.character(as.expression(eq1)), as.character(as.expression(eq2)))
}
labels <- lm_eqn(df)
p <- ggplot(data = df, aes(x = x, y = y)) +
geom_smooth(method = "lm", se=FALSE, color="red", formula = y ~ x) +
geom_point() +
geom_text(x = 75, y = 90, label = labels[1], parse = TRUE, check_overlap = TRUE ) +
geom_text(x = 75, y = 70, label = labels[2], parse = TRUE, check_overlap = TRUE )
print(p)
結果:
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