如何在 python 中水平而不是垂直地合並 output

Question

我有這個 python3 代碼將我的子列表合並到一個列表中：

l=[[4, 5, 6], [10], [1, 2, 3], [10], [1, 2, 3], [10], [4, 5, 6], [1, 2, 3], [4, 5, 6], [4, 5, 6], [7, 8, 9], [1, 2, 3], [7, 8, 9], [1, 2, 3], [4, 5, 6], [7, 8, 9], [4, 5, 6], [10], [7, 8, 9], [7, 8, 9]]

import itertools
merged = list(itertools.chain(*l))

from collections import Iterable

def flatten(items):
    """Yield items from any nested iterable; see Reference."""
    for x in items:
        if isinstance(x, Iterable) and not 
isinstance(x, (str, bytes)):
            for sub_x in flatten(x):
                yield sub_x
        else:
            yield x

merged = list(itertools.chain(*l))
merged

Output 的不良形狀

雖然 output 產生了我想要的，但 output 的形狀不是我想要的 output 以垂直形狀出現，如下所示：

[4,
5,
6,
10,
1,
2,
3,
10,
1,
2,
3,
10,
4,
5,
6,
1,
2,
3,
4,
5,
6,
4,
5,
6,
7,
8,
9,
1,
2,
3,
7,
8,
9,
1,
2,
3,
4,
5,
6,
7,
8,
9,
4,
5,
6,
10,
7,
8,
9,
7,
8,
9]

我想要的 Output 的理想形狀

我寧願希望 output 水平出來，如下所示：

[4, 5, 6, 10, 1, 2, 3, 10, 1, 2, 3, 10, 4, 5, 6, 1, 2, 3, 4, 5, 6, 4, 5, 6, 7, 8, 9, 1, 2, 3, 7, 8, 9, 1, 2, 3, 4, 5, 6, 7, 8, 9, 4, 5, 6, 10, 7, 8, 9, 7, 8, 9]

請幫幫我，我不介意是否有辦法使這種情況與我的代碼不同。

Answer 1

您可以這樣做：

In [5]: for x in merged:
   ...:     print(x, end=' ')
   ...:     
4 5 6 10 1 2 3 10 1 2 3 10 4 5 6 1 2 3 4 5 6 4 5 6 7 8 9 1 2 3 7 8 9 1 2 3 4 5 6 7 8 9 4 5 6 10 7 8 9 7 8 9

Answer 2

而是只使用列表理解：

l=[[4, 5, 6], [10], [1, 2, 3], [10], [1, 2, 3], [10], [4, 5, 6], [1, 2, 3], [4, 5, 6], [4, 5, 6], [7, 8, 9], [1, 2, 3], [7, 8, 9], [1, 2, 3], [4, 5, 6], [7, 8, 9], [4, 5, 6], [10], [7, 8, 9], [7, 8, 9]]

new_l=[j for i in l for j in i]
print(new_l)

輸出：

C:\Users\Desktop>py x.py
[4, 5, 6, 10, 1, 2, 3, 10, 1, 2, 3, 10, 4, 5, 6, 1, 2, 3, 4, 5, 6, 4, 5, 6, 7, 8, 9, 1, 2, 3, 7, 8, 9, 1, 2, 3, 4, 5, 6, 7, 8, 9, 4, 5, 6, 10, 7, 8, 9, 7, 8, 9]

Answer 3

from collections import Counter
import itertools
import operator

list1=[[4, 5, 6], [10], [1, 2, 3], [10], [1, 2, 3], [10], [4, 5, 6], [1, 2, 3], [4, 5, 6], [4, 5, 6], [7, 8, 9], [1, 2, 3], [7, 8, 9], [1, 2, 3], [4, 5, 6], [7, 8, 9], [4, 5, 6], [10], [7, 8, 9], [7, 8, 9]]

dd = [item for sublist in list1 for item in sublist]
print(dd) # method 1

out1 = reduce(operator.concat,list1)
print(out1) # method 2

merged1 = list(itertools.chain.from_iterable(list1))
print(merged1) # method 3

merged2 = list(itertools.chain(*list1))
print(merged2) # method 4