簡體   English   中英

如何將以下查詢轉換為jpa?

[英]How to transform the following query into a jpa?

(SELECT *
  FROM remedi.meds_donation
 WHERE state_short_name IN ('TN')
 AND request_date between "2018-10-01 00:55:48" AND "2018-11-29 13:02:14"
)
 union all
 (SELECT *
  FROM remedi.meds_donation
 WHERE state_short_name NOT IN ('TN')
 AND request_date between "2018-09-01 00:55:48" AND "2018-10-29 13:02:14"
)
 ORDER BY request_date DESC

順序必須是第二個,或者聯合必須是子查詢

也許你是說

SELECT * FROM (

(SELECT *
  FROM remedi.meds_donation
 WHERE state_short_name IN ('TN')
 AND request_date between "2018-10-01 00:55:48" AND "2018-11-29 13:02:14"
)
 union all
 (SELECT *
  FROM remedi.meds_donation
 WHERE state_short_name NOT IN ('TN')
 AND request_date between "2018-09-01 00:55:48" AND "2018-10-29 13:02:14"
)

) T ORDER BY request_date DESC

但我認為更好

SELECT *
      FROM remedi.meds_donation
     WHERE state_short_name NOT IN ('TN')
     AND (request_date between "2018-09-01 00:55:48" AND "2018-10-29 13:02:14" or request_date between "2018-09-01 00:55:48" AND "2018-10-29 13:02:14") 
     ORDER BY request_date DESC

嘗試這個

 SELECT *, (CASE WHEN state_short_name IN ('TN') then 0 else 1 END) as state_order
   FROM remedi.meds_donation
    WHERE request_date between "2018-10-01 00:55:48" AND "2018-11-29 13:02:14"
 ORDER BY state_order asc, request_date DESC

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM