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[英]Python Asyncio is not running new coroutine using asyncio.run_coroutine_threadsafe
[英]Is there a way to run an asyncio coroutine using atexit?
我正在使用 `discord.py 開發一個機器人。 該機器人創建/刪除多個頻道,並連接到 SQLite 數據庫。 如果機器人崩潰了,我希望它能
這是關閉協程:
async def shutdown(self):
print("Shutting down Canvas...")
for ch in self.active_channels:
await client.delete_channel(ch)
self.db.close()
我嘗試過的事情:
# Canv is the interface between the bot and the data we're collecting
atexit.register(canv.shutdown)
bot.run(TOKEN)
try:
bot.loop.run_until_complete(bot.start(TOKEN))
except KeyboardInterrupt or InterruptedError:
bot.loop.run_until_complete(canv.shutdown())
finally:
bot.loop.close()
from async_generator import asynccontextmanager
@asynccontextmanager
async def cleanup_context_manager():
try:
yield
finally:
await canv.shutdown()
with cleanup_context_manager():
bot.run(TOKEN)
這些都不運行canv.shutdown()
,這是一個asyncio.coroutine
。 如何確保此代碼在每種類型的退出時都運行?
我用這篇文章獲取了一些信息,我認為它最接近我想要的。
你可以嘗試這樣的事情
import asyncio
import atexit
@atexit.register
def shutdown(self):
print("Shutting down Canvas...")
loop = asyncio.get_event_loop()
loop.run_until_complete(await_delete_channels())
self.db.close()
async def await_delete_channels(self):
# # Works but it is better to do it asynchronously
# for ch in self.active_channels:
# await client.delete_channel(ch)
#
# Doing delete_channels() asynchronously
delete_channels = [client.delete_channel(ch) for ch in self.active_channels]
await asyncio.wait(delete_channels, return_when=asyncio.ALL_COMPLETED)
嘗試:
try:
bot.loop.run_until_complete(bot.start(TOKEN))
finally:
bot.loop.run_until_complete(canv.shutdown())
bot.loop.close()
您想在每種腳本關閉時刪除頻道並關閉數據庫,而不僅僅是在崩潰時,對嗎?
否則,嘗試:
try:
bot.loop.run_until_complete(bot.start(TOKEN))
except Exception:
bot.loop.run_until_complete(canv.shutdown())
raise
finally:
bot.loop.close()
更新:
根據您提供的鏈接:
可以通過對 sys.exc_info() 的標准調用來檢索引發的異常信息和異常本身。
讓我們試試看:
import sys
try:
bot.loop.run_until_complete(bot.start(TOKEN))
finally:
if sys.exc_info() != (None, None, None):
bot.loop.run_until_complete(canv.shutdown())
bot.loop.close()
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