[英]Python Asyncio is not running new coroutine using asyncio.run_coroutine_threadsafe
[英]Is there a way to run an asyncio coroutine using atexit?
我正在使用 `discord.py 开发一个机器人。 该机器人创建/删除多个频道,并连接到 SQLite 数据库。 如果机器人崩溃了,我希望它能
这是关闭协程:
async def shutdown(self):
print("Shutting down Canvas...")
for ch in self.active_channels:
await client.delete_channel(ch)
self.db.close()
我尝试过的事情:
# Canv is the interface between the bot and the data we're collecting
atexit.register(canv.shutdown)
bot.run(TOKEN)
try:
bot.loop.run_until_complete(bot.start(TOKEN))
except KeyboardInterrupt or InterruptedError:
bot.loop.run_until_complete(canv.shutdown())
finally:
bot.loop.close()
from async_generator import asynccontextmanager
@asynccontextmanager
async def cleanup_context_manager():
try:
yield
finally:
await canv.shutdown()
with cleanup_context_manager():
bot.run(TOKEN)
这些都不运行canv.shutdown()
,这是一个asyncio.coroutine
。 如何确保此代码在每种类型的退出时都运行?
我用这篇文章获取了一些信息,我认为它最接近我想要的。
你可以尝试这样的事情
import asyncio
import atexit
@atexit.register
def shutdown(self):
print("Shutting down Canvas...")
loop = asyncio.get_event_loop()
loop.run_until_complete(await_delete_channels())
self.db.close()
async def await_delete_channels(self):
# # Works but it is better to do it asynchronously
# for ch in self.active_channels:
# await client.delete_channel(ch)
#
# Doing delete_channels() asynchronously
delete_channels = [client.delete_channel(ch) for ch in self.active_channels]
await asyncio.wait(delete_channels, return_when=asyncio.ALL_COMPLETED)
尝试:
try:
bot.loop.run_until_complete(bot.start(TOKEN))
finally:
bot.loop.run_until_complete(canv.shutdown())
bot.loop.close()
您想在每种脚本关闭时删除频道并关闭数据库,而不仅仅是在崩溃时,对吗?
否则,尝试:
try:
bot.loop.run_until_complete(bot.start(TOKEN))
except Exception:
bot.loop.run_until_complete(canv.shutdown())
raise
finally:
bot.loop.close()
更新:
根据您提供的链接:
可以通过对 sys.exc_info() 的标准调用来检索引发的异常信息和异常本身。
让我们试试看:
import sys
try:
bot.loop.run_until_complete(bot.start(TOKEN))
finally:
if sys.exc_info() != (None, None, None):
bot.loop.run_until_complete(canv.shutdown())
bot.loop.close()
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