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[英]ObjectParameterError: Parameter "filter" to findOne() must be an object, got
[英]Mongo filter into GraphQL query | must be an object, got _String_
有一種方法可以通過GraphQL將過濾器選項傳遞給Mongo? 因為我嘗試過這種方式,但是出現了錯誤"message": "Parameter \\"filter\\" to find() must be an object, got {email: \\"test@test.com\\"}",
這是我的查詢類型
users: {
type: new GraphQLList(UserType),
args: {
filter: { type: GraphQLString }
},
resolve(_, { filter }, { req, res }) {
// I tried several ways to get query string and give it to mongo into a object
JSONFilter = JSON.parse(JSON.stringify(filter));
return UserSchema.find(JSONFilter);
}
}
我的查詢看起來像這樣
query myReferrals {
users(filter: "{email: \"test@test.com\"}"){ //I though this should be enough, but no!
referrals{
user{
email
}
}
}
}
這是一個“錯別字”,對我的查詢應該是這樣的:
query myReferrals {
users(filter: "{\"email\": \"test@test.com\"}"){ // Just Add `\"key\"` to key
referrals{
user{
email
}
}
}
}
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