[英]Filter against an array condition
假設我有一個userIds數組
const userIds = ['1234', '3212', '1122']
然后我有一個對象數組
const arrayOfObjects = [
{
_source: {itemId: ['1234'] }
},
{
_source: {itemId: ['3212'] }
},
{
_source: {itemId: ['1111'] }
}
]
我想通過將id與userIds數組匹配來過濾對象數組
arrayOfObjects.filter(item => item._source.itemId === "what goes here?")
嘗試這個
arrayOfObjects.filter(item => userIds.includes(item._source.itemId[0]))
Internet Explorer不支持Array.prototype.includes
。 如果需要跨瀏覽器解決方案,則可以使用Array.prototype.filter
和Array.prototype.indexOf
方法:
const userIds = ['1234', '3212', '1122']; const arrayOfObjects = [{ _source: { itemId: ['1234'] } }, { _source: { itemId: ['3212'] } }, { _source: { itemId: ['1111'] } } ]; const filtered = arrayOfObjects.filter(o => userIds.indexOf(o['_source'].itemId[0]) > -1); console.log(filtered)
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.