根据数组条件过滤

Question

假设我有一个userIds数组

const userIds = ['1234', '3212', '1122']

然后我有一个对象数组

const arrayOfObjects = [
  {
    _source: {itemId: ['1234'] }
  },
  {
    _source: {itemId: ['3212'] }
  },
  {
    _source: {itemId: ['1111'] }
  }
]

我想通过将id与userIds数组匹配来过滤对象数组

arrayOfObjects.filter(item => item._source.itemId === "what goes here?")

Answer 1

尝试这个

arrayOfObjects.filter(item => userIds.includes(item._source.itemId[0]))

Answer 2

Internet Explorer不支持Array.prototype.includes 。 如果需要跨浏览器解决方案，则可以使用Array.prototype.filter和Array.prototype.indexOf方法：

 const userIds = ['1234', '3212', '1122']; const arrayOfObjects = [{ _source: { itemId: ['1234'] } }, { _source: { itemId: ['3212'] } }, { _source: { itemId: ['1111'] } } ]; const filtered = arrayOfObjects.filter(o => userIds.indexOf(o['_source'].itemId[0]) > -1); console.log(filtered)