不支持的操作數類型 (int)+(var) 錯誤

Question

P1Roundx=int (0)
P2Roundx=int(0)
P1Scorex=int(0)
P2Scorex=int(0)
P1Total=int(0)
P2Total=int(0)
number=int(0)
P1R1=int(0)
P2R1=int(0)
P1R2=int(0)
P2R2=int(0)

import time

Username=input("what is player 1’s username") 
Username=str(Username)
if Username == ("1"):
    print ("hello",Username,)
elif Username == ("2"):
    print ("welcome",Username,)
else:
    print("LEAVE!")
    exit()       
          # This module determines if player 1 is authenticated or if they are not. If they are not they are forced to exit the programme

Username2=input("what is player 2's username")
Username2=str(Username2)
if Username2 == ("2"):
    print ("hello,",Username2,)
elif Username2 == ("1"):
    print ("welcome",Username2,)
else:
    print("LEAVE!")
    exit()       

# This module determines if player 2 is authenticated or not and exits the programme if they are not


import random   
P1R1= random.randint(1,6)
P1R1=("Your first roll is",P1R1)
P1R2=random.randint(1,6)
P1R2=("Your second roll is",P1R2)
print("Your total is",P1R1+P1R2)
P1total=P1R1+P1R2

if P1Total % 2 == 0:
    P1Total=(P1Total)+P1R1
else:
    P1Total=(P1Total)-5+P1R1+P1R2

print("Player 1's total score is",P1Total)

import random           
P2R1= random.randint(1,6)
P2R1=("Your first roll is",P2R1)
P2R2=random.randint(1,6)
P2R2=("Your second roll is",P2R2)
print("Your total is",P2R1+P2R2)
P2total=P2R1+P2R2
if P2Total % 2 == 0:
    P2Total=(P2Total)+ P2R1+P2R2
else:
    P2Total=(P2Total)-5+P2R1

print("Player 2's total score is",P2Total)
time.sleep(6)

作為一個錯誤，但我不明白 var + int 在哪里。 我需要幫助。 順便說一句，我不太擅長這個 SNAKEY TING

Answer 1

當您的代碼執行此操作時

P1R1= random.randint(1,6)

P1R1是 1 到 6 之間的數字； 讓我們假設它是 4。但是代碼確實如此

P1R1=("Your first roll is",P1R1)

看來您的意圖是將其作為消息打印出來。 但它實際上所做的是將P1R1的值更改為元組("Your first roll is",4) 。 然后您的代碼繼續執行，好像P1R1仍然具有值4因為它對它進行了加法。

如果您查看此行的輸出：

print("Your total is",P1R1+P1R2)

你會看到它是

Your total is ('Your first roll is', 4, 'Your second roll is', 1)

當很明顯你期待

Your total is 5

你應該很容易明白為什么代碼在那之后出錯了。

Answer 2

嗨刪除以下將元組分配給 P1R1 和 P2R2 的行

P1R1=("Your first roll is",P1R1)
P2R2=("Your second roll is",P2R2)