[英]How to dynamically remove rows from a DataFrame Pandas
我有以下NFL跟蹤數據:
Event PlayId FrameId x-coord y-coord
0 Start 1 1 20.2 20.0
1 NaN 1 2 21.0 19.1
2 NaN 1 3 21.3 18.3
3 NaN 1 4 22.0 17.5
4 End 1 5 22.5 17.2
4 NaN 1 6 22.5 17.2
4 NaN 1 7 22.5 17.2
4 NaN 1 8 22.5 17.2
4 NaN 1 9 22.5 17.2
4 NaN 1 10 22.5 17.2
5 NaN 2 1 23.0 16.9
6 Start 2 2 23.6 16.7
7 End 2 3 25.1 34.1
8 NaN 2 4 25.9 34.2
10 NaN 3 1 22.7 34.2
11 Nan 3 2 21.5 34.5
12 NaN 3 3 21.1 37.3
13 Start 3 4 21.2 44.3
14 NaN 3 5 20.4 44.6
15 End 3 6 21.9 42.7
如何過濾此列表,以僅獲取“事件”列的“開始”和“結束”值之間的行? 為了澄清,這是我要過濾的數據:
Event PlayId FrameId x-coord y-coord
0 Start 1 1 20.2 20.0
1 NaN 1 2 21.0 19.1
2 NaN 1 3 21.3 18.3
3 NaN 1 4 22.0 17.5
4 End 1 5 22.5 17.2
6 Start 2 2 23.6 16.7
7 End 2 3 25.1 34.1
13 Start 3 4 21.2 44.3
14 NaN 3 5 20.4 44.6
15 End 3 6 21.9 42.7
一個明確的解決方案將不起作用,因為實際的數據集非常大,並且無法預測起點和終點值的落差。
與片做的和ffill
那么concat
回來,你還在你的DF有南,它應該是NaN
?
df1=df.copy()
newdf=pd.concat([df1[df.Event.ffill()=='Start'],df1[df.Event=='End']]).sort_index()
newdf
Event PlayId FrameId x-coord y-coord
0 Start 1 1 20.2 20.0
1 NaN 1 2 21.0 19.1
2 NaN 1 3 21.3 18.3
3 NaN 1 4 22.0 17.5
4 End 1 5 22.5 17.2
6 Start 2 2 23.6 16.7
7 End 2 3 25.1 34.1
13 Start 3 4 21.2 44.3
14 NaN 3 5 20.4 44.6
15 End 3 6 21.9 42.7
要么
newdf=df[~((df.Event.ffill()=='End')&(df.Event.isna()))]
newdf
Event PlayId FrameId x-coord y-coord
0 Start 1 1 20.2 20.0
1 NaN 1 2 21.0 19.1
2 NaN 1 3 21.3 18.3
3 NaN 1 4 22.0 17.5
4 End 1 5 22.5 17.2
6 Start 2 2 23.6 16.7
7 End 2 3 25.1 34.1
13 Start 3 4 21.2 44.3
14 NaN 3 5 20.4 44.6
15 End 3 6 21.9 42.7
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.