從用戶輸入 1-10 次 5 次並將它們存儲在一個數組中，如果輸入錯誤，則提示輸入正確

Question

我循環了五次並使用 util.Scanner 獲取用戶輸入，我被困在必須提示用戶正確輸入的部分，以及何時給出正確的輸入並將其存儲在數組中。 然后循環繼續。

while(a<5){
        Scanner input = new Scanner(System.in);
        System.out.println("Please enter the value: ");
        int x = input.nextInt();
        //what code should be added here to prompt user if input is not in 1-10
        //and after checking only, the value should be stored in the array
        userInputs[a] = x;

        a++;
    }

Answer 1

你可以試試：

import java.util.Arrays;
import java.util.Scanner;

public class TakeInput {


    public static void main(String[] args)
    {
        Scanner input= new Scanner(System.in);
        System.out.println("Enter Five Numbers Between 1 and 10");
        double number;
        //set length of array which stores the user input
        double [] arr= new double[5];
        for(int i=0; i<5; i++)
        {
            System.out.println("Enter Input "+i); 

            //accept input from users

            number=input.nextDouble();
            TakeInput ti= new TakeInput();

            //prompts to renter value if value is not valid
            if(ti.validate_input(number)==true)
            {
                arr[i]=number;
            }
            else
            {
                System.out.println("Enter Number "+i+" Again");
                number=input.nextDouble();
            }
        }

        System.out.println("Array List: "+Arrays.toString(arr));
    }


    //validate user input, ensure that input is not out of range
    public boolean validate_input(double input)
    {
        boolean response;
        if(input<=1 || input >=10)
        {
            response=false;
        }
        else
        {
            response=true;
        }
        return response;
    }
}

Answer 2

首先，詢問用戶輸入，並基於此循環並使用掃描儀獲取輸入。

Scanner input= new Scanner(System.in);
System.out.println("Enter Five Numbers");

循環部分：

    int num;
    int [] arr= new int[5];
    for(int i=0; i<arr.length(); i++)
    {
        System.out.println("Enter Input "+i); 
        number=input.nextInt();
        TakeInput ti= new TakeInput();
        if(ti.validate_input(number)==true) arr[i]=number;
        else{
            System.out.println("Enter Number "+i+" Again");
            number=input.nextInt();
        }
    }