[英]create 2D array by replacing * in array values
在二維數組上工作時,必須基於替換以start替換數組值。
我的數組是[ABCD],它必須通過用數組中的*替換1,2,3和4個字符來創建所有可能的組合。
對於EG
* B C D
A * C D
A B * D
A B C * //Replacing 1
* * C D
A * * D
A B * * //Replacing 2
* * * D
A * * *
* B * *
* * C * //Replacing 3
* * * * //Replacing 4
我寫的代碼只是沿對角線更改值。
for(int i=0; i<n; i++)
{
for(int j=0; j<m; j++)
{
// Filling the diagonals with second character
//if(i==j || (i+j)==(n-1))
if(i==j)
A[i][j] = c3;
else // Filling all other positions with second character
A[i][j] = c1;
}
}
for(int i=0; i<n/2; i++)
{
for(int j=i+1; j<m-1-i; j++)
{
// Filling the upper positions.
A[i][j] = c1;
// Filling the lower positions.
A[n-1-i][j] = c1;
}
}
// Printing the Matrix
System.out.println("\nOutput : \n");
for(int i=0; i<n; i++)
{
for(int j=0; j<m; j++)
{
System.out.print(A[i][j]+" ");
}
System.out.println();
}
}
有什么幫助嗎?
這是一個高度概括的版本:
public static char[][] row2array(char... row)
{
// row size
int n = row.length;
// row count in result
int m = 1 << n;
// result two dimensional array
char[][] result = new char[m][n];
// outer loop: rows
for (int i = 0; i < m; ++i) {
// inner loop: columns
for (int j = 0; j < n; ++j) {
// condition: is the bit set?
if ((i & (1 << j)) > 0) {
// if yes, then replace with asterisk
result[i][j] = '*';
} else {
// otherwise just add the element from the row
result[i][j] = row[j];
}
}
}
// finished
return result;
}
System.out.println(Arrays.deepToString(row2array('A', 'B', 'C', 'D')).replace("],", "],\n"));
這使用行索引的位來指定要替換的字符...
這是工作代碼,謝謝您的所有幫助!!!
public class shiftstar {
public static void main(String args[])
{
char colm[]= {'A','B','C','D','E','F','G','H','I'};
int col = colm.length; //Number of Characters as column
int row = 1 << col; //Total Number of Rows
// result two array
char[][] result = new char[row][col];
// outer loop: rows
for (int i = 0; i < row; ++i) {
// inner loop: columns
for (int j = 0; j < col; ++j) {
// condition: is the bit set?
if ((i & (1 << j)) > 0) {
// if yes, then replace with asterisk
result[i][j] = '*';
} else {
// otherwise just add the element from the row
result[i][j] = colm[j];
}
}
}
System.out.println("\nOutput : \n");
for(int i=0; i<row; i++)
{
for(int j=0; j<col; j++)
{
System.out.print(result[i][j]+" ");
}
System.out.println();
}
}
}
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