從python變量中獲取年月日

Question

我想按年，月和日獲得變量的中斷。 這是我得到的：

import datetime
from datetime import date, timedelta
yesterday = date.today() - timedelta(1)
print (yesterday)
year = datetime.date.yesterday.year
month = datetime.date.yesterday.month
day=datetime.date.yesterday.day
print (year)
print (month)
print (day)

我收到了 datetime.date 沒有屬性的錯誤。 我是 python 的完全菜鳥，我被卡住了，任何幫助表示贊賞

Answer 1

你很接近

import datetime
from datetime import date, timedelta
yesterday = date.today() - timedelta(1)
print (yesterday)
year = yesterday.year
month = yesterday.month
day=yesterday.day
print (year)
print (month)
print (day)

結果是

2019-03-10

2019年

3

10

Answer 2

您還可以像這樣簡化導入語句：

from datetime import datetime, timedelta

yesterday = datetime.today() - timedelta(1)

print(yesterday)

year = yesterday.year
month = yesterday.month
day = yesterday.day

print(year)
print(month)
print(day)

你會得到輸出：

2019-03-10 21:19:36.695577
2019
3
10

Answer 3

您可以使用strftime方法

一個簡單的例子：

>>> from datetime import datetime
>>> now = datetime.utcnow()
>>> year_month_day_format = '%Y-%m-%d'
>>> now.strftime(year_month_day_format)
'2020-11-06'
>>> hour_minute_format = '%H:%M'
>>> now.strftime(hour_minute_format)
'22:54'

跳，它會幫助某人

Answer 4

對於當天

import datetime

current_datetime=datetime.datetime.now()
print("current_year:{}".format(current_datetime.year))
print("current_month:{}".format(current_datetime.month))
print("current_day:{}".format(current_datetime.day))

Answer 5

如果您想要這種格式，例如“10-Oct-2018”。 您可以在當天嘗試此代碼。

from datetime import datetime, timezone

now_utc = datetime.now(timezone.utc)
year = now_utc.strftime("%Y")
month = now_utc.strftime("%b")
day = now_utc.strftime("%d")
result = day+"-"+month+"-"+year

print(result)