[英]Create a list of dictionaries with unique keys from a list of dictionaries with duplicated keys
我有一個詞典列表:
records = [{id:123, name:'Course A', enrolled_date:'1st Feb'},
{id:123, name:'Course A', enrolled_date:'1st Jan'},
{id:456, name:'Course B', enrolled_date:'1st Jan'}]
我想從這些數據中創建一個新的字典列表。 新列表應該只包含在該列表范圍內具有唯一ids
字典,例如:
new_records = [{id:123, name:'Course A'},
{id:456, name:'Course B'}]
這是我到目前為止嘗試過的代碼。 它顯然不起作用 - 但我已經用盡所有努力來糾正它。
new_records = []
for record in records:
new_id = record['id']
new_name = record['name']
new_dict = {'id':new_id, 'name',new_name}
If new_id not in new_records:
new_records.append(new_dict)
這是基於您提供的代碼,但對於大型列表,它的工作確實非常慢,如其他注釋中所述。
new_records = []
for record in records:
new_id = record['id']
new_name = record['name']
new_dict = {'id':new_id, 'name': new_name}
if not any(new_record['id'] == new_id for new_record in new_records):
new_records.append(new_dict)
您也可以通過使用一組已經“看到”的條目過濾數組來完成此操作:
records = [{"id":123, "name":'Course A', "enrolled_date":'1st Feb'},
{"id":123, "name":'Course A', "enrolled_date":'1st Jan'},
{"id":456, "name":'Course B', "enrolled_date":'1st Jan'}]
seen = set()
new_dict = [d for d in records if not(d['id'] in seen or seen.add(d['id']))]
# {'id': 123, 'name': 'Course A', 'enrolled_date': '1st Feb'}
# {'id': 456, 'name': 'Course B', 'enrolled_date': '1st Jan'}
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