PHP發布如何在foreach循環中獲取選項的值以顯示所選值

Question

我在一個旅館的桌子上有5個房間，並且用戶必須檢查他們想要預訂的一個或多個房間，並選擇他們希望擁有的選項，例如人數，早餐選項，晚餐選項和床選項。

假設我們按出現順序將這5個房間稱為：

元素室

地球室

水室

航空室

消防室

如果我按從上到下的順序選擇房間（例如元素到火的房間），則會得到結果選項，但是如果我選擇兩者之間的任何房間，則得到0。 從復選框中選中房間名稱時，房間名稱始終正確顯示，但選項值顯示為0（第一個房間（元素）除外）

HTML：

<form class="booking-form" name="book-room-form" action="" id="contactForm" method="post" novalidate>

<?php foreach ( $rooms as $room ) : ?>

<input type="checkbox" class="form-check-input" name="room-selected[]" value="<?php echo $room->post_title; ?>">

<select class="num-person select-update" id="<?php echo 'r-' . $room->ID; ?>" name="people-select[]" required>
  <option value="0" selected>Select Number of Persons</option>
  <option value="1">1 person R600</option>
  <option value="2">2 persons R800</option>
</select>

<select class="num-dinner select-update" id="<?php echo 'd-' . $room->ID; ?>" name="dinner-select[]">
    <option value="0" selected>Select Dinner Course</option>
    <option value="120">Two Course Dinner R120</option>
    <option value="200">Three Course Dinner R200</option>
</select>

<select class="num-bf select-update" id="<?php echo 'b-' . $room->ID; ?>" name="breakfast-select[]">
    <option value="0" selected>Select Breakfast Type</option>
    <option value="70">Basic Breakfast R70</option>
    <option value="120">Full Breakfast R120</option>
</select>

<select class="bed-select" name="bed-select[]">
    <option selected>Select Bed Size</option>
    <option value="King Bed">King Bed</option>
    <option value="2 Single Beds">2 Single Beds</option>
</select>



<?php endforeach; ?>

    <button name="submit-request" type="submit" class="btn btn-primary">Submit</button>
</form>

碼：

if(isset($_POST['submit-request'])) {

    $room_selected = $_POST['room-selected'];
    $numPeople = $_POST['people-select'];
    $dinnerSelect = $_POST['dinner-select'];
    $breakfastSelect = $_POST['breakfast-select'];
    $bedSelect = $_POST['bed-select'];

    $room = $room_selected;
    $num = $numPeople;
    $dinn = $dinnerSelect;
    $bf  = $breakfastSelect;
    $bed = $bedSelect;

    foreach ($room as $id => $key) {
    //$key returns the room name
      if($key) {
        $result[$key] = array(
            'num_person'  => $num[$id],
            'dinner' => $dinn[$id],
            'breakfast'    => $bf[$id],
            'bed_type' => $bed[$id],
        );
    }

    echo $key . '<br/>' . $num[$id] . '<br/>' . $dinn[$id] . '<br/>' . $bf[$id] . '<br/>' . $bed[$id] . '<br/>' ;

    }

}

我希望能夠選擇任何房間並顯示選項值

Answer 1

我之所以這樣說是因為您沒有在HTML表單數組中使用任何鍵。 當前的解決方案有些脆弱，因此您要么需要在字段命名中更加具體，要么將鍵包含在數組中。

<?php foreach ( $rooms as $room ) : ?>

<input type="checkbox" class="form-check-input" name="room-selected[]" value="<?php echo $room->post_title; ?>">

<select class="num-person select-update" id="<?php echo 'r-' . $room->ID; ?>" name="people-select[<?php echo $room->post_title; ?>]" required>
  <option value="0" selected>Select Number of Persons</option>
  <option value="1">1 person R600</option>
  <option value="2">2 persons R800</option>
</select>

<select class="num-dinner select-update" id="<?php echo 'd-' . $room->ID; ?>" name="dinner-select[<?php echo $room->post_title; ?>]">
    <option value="0" selected>Select Dinner Course</option>
    <option value="120">Two Course Dinner R120</option>
    <option value="200">Three Course Dinner R200</option>
</select>

<select class="num-bf select-update" id="<?php echo 'b-' . $room->ID; ?>" name="breakfast-select[<?php echo $room->post_title; ?>]">
    <option value="0" selected>Select Breakfast Type</option>
    <option value="70">Basic Breakfast R70</option>
    <option value="120">Full Breakfast R120</option>
</select>

<select class="bed-select" name="bed-select[<?php echo $room->post_title; ?>]">
    <option selected>Select Bed Size</option>
    <option value="King Bed">King Bed</option>
    <option value="2 Single Beds">2 Single Beds</option>
</select>

<?php endforeach; ?>

然后，在運行循環而不是檢查$ id時，請使用$ key。

if(isset($_POST['submit-request'])) {

    $room_selected = $_POST['room-selected'];
    $numPeople = $_POST['people-select'];
    $dinnerSelect = $_POST['dinner-select'];
    $breakfastSelect = $_POST['breakfast-select'];
    $bedSelect = $_POST['bed-select'];

    $room = $room_selected;
    $num = $numPeople;
    $dinn = $dinnerSelect;
    $bf  = $breakfastSelect;
    $bed = $bedSelect;

    foreach ($room as $id => $key) {
    //$key returns the room name
      if($key) {
        $result[$key] = array(
            'num_person'  => $num[$key],
            'dinner' => $dinn[$key],
            'breakfast'    => $bf[$key],
            'bed_type' => $bed[$key],
        );
    }

    echo $key . '<br/>' . $num[$key] . '<br/>' . $dinn[$key] . '<br/>' . $bf[$key] . '<br/>' . $bed[$key] . '<br/>' ;

    }

}