[英]Return values under same column in SPARQL query
給定三個可能的三元組對象, foaf:name
, foaf:givenName
和foaf:familyName
,其中語句要么有foaf:name
要么foaf:givenName
+ foaf:familyName
,例如:
<uri1> <foaf:name> "Lolly Loozles" .
<uri2> <foaf:givenName> "Stotly" .
<uri2> <foaf:familyName> "Styles" .
想知道如何編寫一個 SPARQL 查詢來返回一個新變量,比如pretty_name
,它要么是foaf:name
的值,要么是來自foaf:givenName
和foaf:familyName
的值的串聯。
導致類似:
?o | ?pretty_name
----------------------
<uri1> | Lolly Loozles
<uri2> | Stotly Styles
到目前為止,這是我所擁有的,但不確定如何進行:
PREFIX : <https://example.org/>
PREFIX foaf: <http://xmlns.com/foaf/0.1/>
# select two variables, not ideal...
SELECT ?foaf_fullName ?pretty_name
WHERE {
# Find all triples
?s ?p ?o .
# Binds
OPTIONAL { ?s foaf:name ?foaf_fullName }
OPTIONAL { ?s foaf:givenName ?givenName }
OPTIONAL { ?s foaf:familyName ?familyName }
# Filter where predicate is part of list
FILTER (?p IN (foaf:name, foaf:givenName, foaf:familyName ) )
# Binds
BIND( CONCAT(?givenName, ' ', ?familyName) AS ?pretty_name ) .
}
我曾想象並嘗試添加另一個BIND
以添加到?pretty_name
,但 SPARQL 引擎沒有它:
BIND( ?foaf_fullName AS ?pretty_name ) .
我也很幸運地寫了一個CONSTRUCT
語句來獲取我正在尋找的值,但沒有能力寫回這個三元組(出於多種原因):
CONSTRUCT {
?s :hasPrettyName ?foaf_fullName .
?s :hasPrettyName ?pretty_name .
}
我原以為CONSTRUCT
可以伴隨SELECT
,但一定是錯的?
任何見解或建議將不勝感激。
使用@StanislavKralin 評論/建議在沒有IF
子句的情況下使用COALESCE
效果很好:
PREFIX : <https://example.org/>
PREFIX foaf: <http://xmlns.com/foaf/0.1/>
# select two variables, not ideal...
SELECT ?foaf_fullName ?pretty_name
WHERE {
# Find all triples
?s ?p ?o .
# Binds
OPTIONAL { ?s foaf:name ?foaf_fullName }
OPTIONAL { ?s foaf:givenName ?givenName }
OPTIONAL { ?s foaf:familyName ?familyName }
# Filter where predicate is part of list
FILTER (?p IN (foaf:name, foaf:givenName, foaf:familyName ) )
# Binds
BIND( COALESCE(?foaf_fullName, CONCAT(?givenName, ' ', ?familyName)) AS ?pretty_name )
}
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